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Scilla [17]
3 years ago
8

Sesh wants to create a device to transmit an electrical current. He has the following materials: pure water (H2O), brass (Cu3Zn2

) foil, solid calcium chloride (CaCl2), solid sugar (C12H22O11), pure methane (CH4), and a Bunsen burner. Describe two ways he could use these materials to transmit electricity. Assume that he has access to all necessary glassware and other equipment. Explain your choices using the properties of ionic, covalent, and metallic substances.
Chemistry
2 answers:
Viktor [21]3 years ago
8 0
Here are two ways how he<span> could use these materials to transmit electricity: 

The first one is to carry the current due to the fact that metals conduct electricity in a needed condition only when they are solid.And since dissolved ionic compounds are good for conducting electricity - make a dissolving. Such materials as methane, water and sugar are not suitable as they are covalent compounds, that, as you know can not conduct an electric current.

Do hope it will help you!</span>
pav-90 [236]3 years ago
3 0

Use the brass foil to carry the current, because metals conduct electricity well in the solid state.


Dissolve the calcium chloride in water, because ionic compounds conduct electricity well when dissolved.


Pure water, sugar, or methane are not useful because they are covalent compounds and do not conduct an electric current.

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Answer:

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Kf = 0

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4 years ago
What is the difference between a forklift and a hi-lo?
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5 0
3 years ago
Classify each of the following properties of a cake as qualitative or quantitative. Give reasons for your answers
VashaNatasha [74]

Answer:

The answer to your question is below

Explanation:

A qualitative property of matter is a property characteristic of a substance like color and flavor.

A quantitative property of matter is a property when we get a number.

A) it's a circular shape  is a qualitative property because the shape is a qualitative property and shape is not represented by a number.

B) its mass is 1.5 kg  is a quantitative property because we know a number of this mass.

C) it tastes like chocolate  is a qualitative property because the flavor is characteristic of a substance and flavor is not measured in numbers.

D) it is 30 cm in diameter  it is a quantitative property, we know the exact dimension of it.

E) its icing is melting is a qualitative property, melting is a property of ice, it just happens.

4 0
4 years ago
Three of the reactions that occur when the paraffin of a candle (typical formula C21H44) burns are as follows:
Katarina [22]

Answer and Explanation:

The 3 reactions represented are

C₂₁H₄₄ + 32O₂ -----> 21CO₂ + 22H₂O

C₂₁H₄₄ + (43/2)O₂ -----> 21CO + 22H₂O

C₂₁H₄₄ + 11O₂ -----> 21C + 22H₂O

ΔH°(C₂₁H₄₄) = -476 KJ/mol, ΔH°(O₂) = 0KJ/mol, ΔH°(CO₂) = -393.5 KJ/mol, ΔH°(CO) = -99 KJ/mol, ΔH°(H₂O) = -292.74 KJ/mol, ΔH°(C) = 0KJ/mol

ΔH°f = ΔH°(products) - ΔH°(reactants)

For reaction 1,

ΔH°(products) = 21(ΔH°(CO₂)) + 22(ΔH°(H₂O)) = 21(-393.5) + 22(-292.74) = -14703.78 KJ/mol

ΔH°(reactants) = ΔH°(C₂₁H₄₄) = -476 KJ/mol

ΔH°f = -14703.78 - (-476) = - 14227.78 KJ/mol

For reaction 2,

ΔH°(products) = 21(ΔH°(CO)) + 22(ΔH°(H₂O)) = 21(-99) + 22(-292.74) = -8519.28 KJ/mol

ΔH°(reactants) = ΔH°(C₂₁H₄₄) = -476 KJ/mol

ΔH°f = -8519.28 - (-476) = - 8043.28 KJ/mol

For reaction 3,

ΔH°(products) = 21(ΔH°(C)) - 22(ΔH°(H₂O)) = 21(0) + 22(-292.74) = -6440.28 KJ/mol

ΔH°(reactants) = ΔH°(C₂₁H₄₄) = -476 KJ/mol

ΔH°f = -6440.28 - (-476) = - 5968.28 KJ/mol

b) To obtain the q for the combustion of 254g of paraffin, we convert the mass to moles.

Number of moles = mass/molar mass; molar mass of C₂₁H₄₄ = 296 g/mol

Number of moles = 254/296 = 0.858 mole

heat of reaction for the combustion of C₂₁H₄₄ when it is complete combustion, q = ΔH°(complete combustion, i.e. reaction 1) × number of moles = -14227.78 × 0.858 = -12207.435 KJ/mol

c) 8% of the mass of C₂₁H₄₄ undergoes incomplete combustion = 8% × 254 = 20.32g, in number of moles = 20.32/296 = 0.0686 mole

5% of the mass of C₂₁H₄₄ becomes soot = 5% × 254 = 12.7g, in number of moles = 12.7/296 = 0.0429 mole

The remaining paraffin undergoes complete combustion = 87% of 254 = 220.98g, in number of moles = 220.98 = 0.747 mole

q = sum of all the heat of reactions = (0.747 × -14227.78) + (0.0686 × -8043.28) + ( 0.0429 × -5968.28) = -11435.377 KJ

QED!!!

8 0
3 years ago
Carbon-14 has a half-life of 5730 years. How old would a real fossil be after 4 carbon-14 half-lives? Show work
Liono4ka [1.6K]

Answer: 22920 years

Explanation:

Every 5730, the carbon-14 is halved.

After 4 of such cycles, meaning 5730 * 4 = 22920 years

5 0
3 years ago
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