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Gnoma [55]
4 years ago
12

Can anyone show how they solved this really need help

Mathematics
2 answers:
charle [14.2K]4 years ago
6 0
The total number of degrees in would be 720. By subtracting all other angles you will find x.

720-129-105-135-130-95=126

X=126
dlinn [17]4 years ago
5 0
Yeah! if you add all the measurements together without x, you’d get 594 degrees. if you take the required degrees for a hexagon (720) and subtract 594, you’d get 126. therefore, the missing measurement is 126 degrees.

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Hall and Mindy are playing a guessing game. Hall tells Mindy: ""The difference between 17 and the square root of my mystery numb
cestrela7 [59]

Answer:

The possible number that Hall could be thinking of is 144.

Step-by-step explanation:

Difference between 17 and the square root of my mystery number

This is represented by:

17 - \sqrt{x}

is 5

Then:

17 - \sqrt{x} = 5

What are two possible numbers that Hall could be thinking of?

We have to solve the equation, for x. So

17 - \sqrt{x} = 5

\sqrt{x} = 12

(\sqrt{x})^2 = (12)^2

x = 144

The possible number that Hall could be thinking of is 144.

5 0
3 years ago
Given the quadratic equation x2 - 5x+ 10 = 0
Rudik [331]
The answer is 4/10*cos 01
5 0
3 years ago
Suppose that the population of the scores of all high school seniors who took the SAT Math (SAT-M) test this year follows a Norm
Vlad1618 [11]

Answer:

Confidence =1-\alpha=1-0.01=0.99

And then the confidence level would be given by 99%

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

X \sim N(\mu, \sigma)

The distribution for the sample mean is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\bar x =512 represent the sample mean

\sigma=100 represent the population standard deviation

n= 100 sample size selected.

The confidence interval is given by this formula:

\bar X \pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}   (1)

The marginof error for this case is given by Me=25.76. And we know that the formula for the margin of error is given by:

Me=z_{\alpha/2} \frac{\sigma}{\sqrt{n}}

25.76=z_{\alpha/2} \frac{100}{\sqrt{100}}

And we can find the critical value z_{\alpha/2} like this:

z_{\alpha/2}=\frac{25.76(\sqrt{100})}{100}=2.576

And we know that on the right tail of the z score =2.576 we have \alpha/2 of the total area. We can find the area on the right of the z score using this excel code:

"=1-NORM.DIST(2.576,0,1,TRUE)" or using a table of the normal standard distribution, and we got 0.004998=\alpha/2, so then \alpha=0.00498*2=0.009995 \approx 0.01, and then we can find the confidence like this:

Confidence =1-\alpha=1-0.01=0.99

And then the confidence level would be given by 99%

8 0
3 years ago
Https://brainly.com/question/20878368
kodGreya [7K]

Answer:

Step-by-step explanation:

4 0
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Answer:

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