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allsm [11]
3 years ago
14

I need help !!!!!!!!!!!!!!!

Mathematics
2 answers:
Dominik [7]3 years ago
4 0
Because \angle A and \angle B are alternate exterior angles, this means they <span>congruent or equal to each other.
</span>
Therefore, we can say 5x-15 = 2x+21 and use this equation to solve for x.
5x-15 = 2x+21
5x = 2x+36
3x = 36
x = 12
So x is equal to 12. After finding this, we can now go back to the equation for \angle B and plugin x to solve it.
\angle B = 2x +21

\angle B = 2(12) +21
\angle B = 24 +21
\angle B = 45
Therefore, \angle B is equal to 45 degrees.


koban [17]3 years ago
3 0
Angle B= 45 degrees
Angle A = 45 degrees

A and B are congruent since they are alternate exterior angles
5x-15 = 2x +21
5x = 2x +36
3x=36
X=12
B)
2x12+21 = 45
A)
5x12-15 =45
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What is the distance rounded to the nearest tenth between the points (2 -2) and (6 3)
kotegsom [21]

Answer:

The distance between the points is approximately 6.4

Step-by-step explanation:

The given coordinates of the points are;

(2, -2), and (6, 3)

The distance between two points, 'A', and 'B', on the coordinate plane given their coordinates, (x₁, y₁), and (x₂, y₂) can be found using following formula;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

Substituting the known 'x', and 'y', values for the coordinates of the points, we have;

l_{(2, \, -2), \ (6, \, 3) } = \sqrt{\left (3-(-2)  \right )^{2}+\left (6-2  \right )^{2}} = \sqrt{5^2 + 4^2} = \sqrt{41}

Therefore, the distance between the points, (2, -2), and (6, 3) = √(41) ≈ 6.4.

4 0
3 years ago
Prove by mathematical induction that 1+2+3+...+n= n(n+1)/2 please can someone help me with this ASAP. Thanks​
Iteru [2.4K]

Let

P(n):\ 1+2+\ldots+n = \dfrac{n(n+1)}{2}

In order to prove this by induction, we first need to prove the base case, i.e. prove that P(1) is true:

P(1):\ 1 = \dfrac{1\cdot 2}{2}=1

So, the base case is ok. Now, we need to assume P(n) and prove P(n+1).

P(n+1) states that

P(n+1):\ 1+2+\ldots+n+(n+1) = \dfrac{(n+1)(n+2)}{2}=\dfrac{n^2+3n+2}{2}

Since we're assuming P(n), we can substitute the sum of the first n terms with their expression:

\underbrace{1+2+\ldots+n}_{P(n)}+n+1 = \dfrac{n(n+1)}{2}+n+1=\dfrac{n(n+1)+2n+2}{2}=\dfrac{n^2+3n+2}{2}

Which terminates the proof, since we showed that

P(n+1):\ 1+2+\ldots+n+(n+1) =\dfrac{n^2+3n+2}{2}

as required

4 0
3 years ago
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Illusion [34]

Answer:

x+3-5 i think

Step-by-step explanation:

"and" means add so x+3 and subtract 5

6 0
3 years ago
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marysya [2.9K]

Answer:

Z = 20

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Please help me with this question
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Answer:

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Step-by-step explanation:

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