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Zinaida [17]
3 years ago
15

Write down the first five terms of a sequence where the nth term is given by n2 – 5

Mathematics
1 answer:
zhuklara [117]3 years ago
6 0
-3 , -1 , 1 , 3 , 5
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7 0
3 years ago
The answer to this question
oee [108]
If the cell phone company charges a flat $40 fee monthly, then the equation would be y = 40.


The company does charge $40 a month, but also charges $2 per minute out of service area (x).

So the equation is y = 2x + 40

To graph this linear function, plug in values for x then plot the plots. Then draw a line to connect the points.

y = f(x)

f(0) = 40
f(1) = 42
f(2) = 44
f(3) = 46
f(4) = 48
f(5) = 50

So at x=0, draw a point at y=40 and so on.






6 0
3 years ago
A survey of 25 young professionals fond that they spend an average of $28 when dining out, with a standard deviation of $10. (a)
skad [1K]

Answer:

a) The 95% of confidence intervals for the average spending

(23.872 , 32.128)

b) The calculated value t= 1< 1.711( single tailed test) at 0.05 level of significance with 24 degrees of freedom.

The null hypothesis is accepted

A survey of 25 young professionals statistically that the population mean is less than $30

<u>Step-by-step explanation</u>:

Step:-(i)

Given data a survey of 25 young professionals fond that they spend an average of $28 when dining out, with a standard deviation of $10

The sample size 'n' = 25

The mean of the sample   x⁻  = $28

The standard deviation of the sample (S) = $10.

Level of significance ∝=0.05

The degrees of freedom γ =n-1 =25-1=24

tabulated value t₀.₀₅ = 2.064

<u>Step 2:-</u>

The 95% of confidence intervals for the average spending

((x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } ,x^{-} + t_{\alpha }\frac{S}{\sqrt{n} } )

(28 - 2.064 \frac{10}{\sqrt{25} } ,28 + 2.064\frac{10}{\sqrt{25} } )

( 28 - 4.128 , 28 + 4.128)

(23.872 , 32.128)

a) The 95% of confidence intervals for the average spending

(23.872 , 32.128)

b)

Null hypothesis: H₀:μ<30

Alternative Hypothesis: H₁: μ>30

level of significance ∝ = 0.05

The test statistic

t = \frac{x^{-}-mean }{\frac{S}{\sqrt{n} } }

t = \frac{28-30 }{\frac{10}{\sqrt{25} } }

t = |-1|

The calculated value t= 1< 1.711( single tailed test) at 0.05 level of significance with 24 degrees of freedom.

The null hypothesis is accepted

<u>Conclusion</u>:-

The null hypothesis is accepted

A survey of 25 young professionals statistically that the population mean is less than $30

8 0
3 years ago
I need two equations to use elimination but I don't know what equations to use.
lyudmila [28]
2x+3y=160
-2x+7y=25 I hope that helps!!
7 0
3 years ago
Read 2 more answers
Phil and matt made cookies for a fundraiser at their high school answer
lapo4ka [179]
<span>Phil and Matt made cookies for a fundraiser at their high school. Phil worked more than Matt. Phil production was 25% more than Matt production. Matt was behind on the quantity made by Phil. The cookies sold for $0.25 each. After the sale, 20% of the combined production of their cookies remained.</span>
5 0
3 years ago
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