Answer:
1) is not possible
2) P(A∪B) = 0.7
3) 1- P(A∪B) =0.3
4) a) C=A∩B' and P(C)= 0.3
b) P(D)= 0.4
Step-by-step explanation:
1) since the intersection of 2 events cannot be bigger than the smaller event then is not possible that P(A∩B)=0.5 since P(B)=0.4 . Thus the maximum possible value of P(A∩B) is 0.4
2) denoting A= getting Visa card , B= getting MasterCard the probability of getting one of the types of cards is given by
P(A∪B)= P(A)+P(B) - P(A∩B) = 0.6+0.4-0.3 = 0.7
P(A∪B) = 0.7
3) the probability that a student has neither type of card is 1- P(A∪B) = 1-0.7 = 0.3
4) the event C that the selected student has a visa card but not a MasterCard is given by C=A∩B' , where B' is the complement of B. Then
P(C)= P(A∩B') = P(A) - P(A∩B) = 0.6 - 0.3 = 0.3
the probability for the event D=a student has exactly one of the cards is
P(D)= P(A∩B') + P(A'∩B) = P(A∪B) - P(A∩B) = 0.7 - 0.3 = 0.4
Answer:
Each would equal 10 lbs.
Step-by-step explanation:
60 pounds all together is the weight of 6 boxes, so if you divide 60 by 6, you'll get 10 lbs for each box.
All work<span> should be submitted in its original form. ... (b) </span>If<span> v=— </span>show<span> that z=a^~^\ and </span>find<span> from either equation 1 ' " x-a' p—a' H the </span>value<span> of a in order that </span>x<span>='i when y=2. Also, for this ... Thence </span>find<span> the length of an edge of such a box weighing </span>18<span>$ pounds, </span>if<span> the thickness is 1 inch and the weight 1 ounce to the cubic inch.</span>
1.69 is 1.3 to the second power
You forgot to put the options and the rest of the equation
