All categories

3 years ago

Help please! Picture included about functions. Explain if you can.

Mathematics

1 answer:

slega [8]3 years ago

3 0

The definition of a function is a relation where every input (x value) is paired with exactly one output (y-value).

A. Not a function, because you have (300, 9) and (300,7). The x-value 300 is paired with two different y-values, 9 and 7.

B. Not a function. (260, 4) and (260, 2)

C. Is a function

D. Not a function. (225, 4) and (225, 2)

You might be interested in

At the beginning of the week, Paloma opened a new box of 100 coffee creamers. Sixty-seven coffee creamers were used during the w

Sergio [31]

The answer would be 100 - 67 = 33

8 0

3 years ago

Read 2 more answers

BRAINLIEST FOR RIGHT ANSWER!!

julsineya [31]

Answer: ${\boxed{h(x+4)=\frac{9+3x}{8+x}}}$

Concept:

In a function f(x), it represents a function in terms of x or for x. Therefore, to find the values in the function, substitute values within the parenthesis to solve.

Solve:

Given information

$h(x)=\frac{-3+3x}{4+x}$

Need to find

$h(x+4)$

Substitute (x + 4) to the position of x

$h(x+4)=\frac{-3+3(x+4)}{4+(x+4)}$

Distributive property on the numerator

$h(x+4)=\frac{-3+3x+12}{4+(x+4)}$

Combine like terms

$h(x+4)=\frac{-3+12+3x}{4+4+x}$

$\boxed{h(x+4)=\frac{9+3x}{8+x}}$

Hope this helps!! :)

Please let me know if you have any questions

5 0

2 years ago

Find the volume of a cone with a diameter of 12 m and a height of 6 m.

castortr0y [4]

Answer: D. 72 m

Step-by-step explanation:

The formula for the volume of a cone is Volume = pi times radius squared and then times the height, and then divided by 3.

Since the diameter is 12, the radius is 6. Applying the formula, 6 squared is 36, times pi is 36 pi. The height is 6 so 36 * 6 = 216.

But be careful, we're not done yet... We still have to divide by 3

216 / 3 = 72

we can be sure this answer is correct because the other answers are clearly too big

here's your answer, hope this helps :)

3 0

2 years ago

Why does the fact family for 81 and 9 only have two number sentences?

sukhopar [10]

Because, 9 x 9 = 81. Hope I helped!

6 0

3 years ago

Given the function f(x) = x^4 + 3x^3 - 2x^2 - 6x - 1, use intermediate theorem to decide which of the following intervals contai

marta [7]

$f(x) = x^4 + 3x^3 - 2x^2 - 6x - 1$

Lets check with every option

(a) [-4,-3]

We plug in -4 for x and -3 for x

$f(-4) = (-4)^4 + 3(-4)^3 - 2(-4)^2 - 6(-4) - 1= 55$

$f(-3) = (-3)^4 + 3(-3)^3 - 2(-3)^2 - 6(-3) - 1= -1$

f(-4) is positive and f(-3) is negative. there is some value at x=c on the interval [-4,-3] where f(c)=0. so there exists atleast one zero on this interval.

(b) [-3,-2]

We plug in -3 for x and -2 for x

$f(-3) = (-3)^4 + 3(-3)^3 - 2(-3)^2 - 6(-3) - 1= -1$

$f(-2) = (-2)^4 + 3(-2)^3 - 2(-2)^2 - 6(-2) - 1= -5$

f(-2) is negative and f(-3) is negative. there is no value at x=c on the interval [-3,-2] where f(c)=0.

(c) [-2,-1]

We plug in -2 for x and -1 for x

$f(-2) = (-2)^4 + 3(-2)^3 - 2(-2)^2 - 6(-2) - 1= -5$

$f(-1) = (-1)^4 + 3(-1)^3 - 2(-1)^2 - 6(-1) - 1= 1$

f(-2) is negative and f(-1) is positive. there is some value at x=c on the interval [-2,-1] where f(c)=0. so there exists atleast one zero on this interval.

(d) [-1,0]

We plug in -1 for x and 0 for x

$f(-1) = (-1)^4 + 3(-1)^3 - 2(-1)^2 - 6(-1) - 1= 1$

$f(0) = (0)^4 + 3(0)^3 - 2(0)^2 - 6(0) - 1= -1$

f(-1) is positive and f(0) is negative. there is some value at x=c on the interval [-1,0] where f(c)=0. so there exists atleast one zero on this interval.

(e) [0,1]

We plug in 0 for x and 1 for x

$f(0) = (0)^4 + 3(0)^3 - 2(0)^2 - 6(0) - 1= -1$

$f(1) = (1)^4 + 3(1)^3 - 2(1)^2 - 6(1) - 1= -5$

f(0) is negative and f(1) is negative. there is no value at x=c on the interval [0,1] where f(c)=0.

(f) [1,2]

We plug in 1 for x and 2 for x

$f(1) = (1)^4 + 3(1)^3 - 2(1)^2 - 6(1) - 1= -5$

$f(2) = (2)^4 + 3(2)^3 - 2(2)^2 - 6(2) - 1= 19$

f(-4) is positive and f(-3) is negative. there is some value at x=c on the interval [-4,-3] where f(c)=0. so there exists atleast one zero on this interval.

so answers are (a) [-4,-3], (c) [-2,-1], (d) [-1,0], (f) [1,2]

8 0

3 years ago

Read 2 more answers