Answer:
15
Step-by-step explanation:
Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.
2(x+y) = 300
x+y = 150
y = 150-x
A=x(150-x) <--(substitution)
The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
0=x(150-x)
x=0, 150
So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.
A=75(150-75)
A=75*75
A=5625
So the maximum area that can be enclosed is 5625 square feet.
area of the parallelogram is: b x h
12 x 4 = 48 (d)
8 x (5 x 2 + 3)= 8 x ( 15 + 3) = 8 x 13 = 104.
Hope I helped!(:
(a). To calculate Y at equilibrium
Y = C + I + G
Y = 40 + 0.8(Y – 0 + 10 + 20)
Y = 350
(b). To calculate C, I and G at Equilibrium
C = 40 + 0.8 Y
Since Y = 350
C = 40 + 0.8(350)
C = 40 + 280
C = 320
I = 20
G = 10
(c).To find
equilibrium Y
Given,
EX = 4 + 3EP/P
IM = 8 + 0.1 (Y - T) - 2EP/P
E = 3
P = 1
P = 1.5
Y = 170
