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nata0808 [166]
3 years ago
6

Just need the answers for these 3 questions please, and how to do them (:

Mathematics
2 answers:
Darya [45]3 years ago
6 0

Answer:

a) 7

b)64

c)2

Step-by-step explanation:

look at images

WITCHER [35]3 years ago
6 0

Answer:

x = 2

Step-by-step explanation:

The topic here is "fractional exponents."

Review:  2^3 = 8 (this is the cube of 2), and so the inverse function is

            8^(1/3) = 2    ("8 raised to the fractional exponent 1/3 is 2"

Question a)  49^(1/2) ("49 to the power 1/2") can be rewritten as

(7^2)^(1/2), which simplifies to 7^(2*1/2) = 7^1  =  7

Caution:  this is exponentiation, not division.  So 49^(1/2) does not equal 49/2.

Question b)     (     )^(1/3)  =  4

I would prefer to write this as x^(1/3) = 4 and set the goal of finding the value of the base, x.

Then x^(1/3) = 4   ("x raised to the power 1/3 is 4")

Let's elimiinate the fractional exponent on the left by cubing both sides of the equation:

{x^(1/3)}^3 = 4^3, or, after simplification,

x^1 = 64, or, in simplest form,

x = 64

Question c)

Notice that the base here is 1/100

and that the square root of 1 is 1 and that of 100 is 10.

Therefore, the given

{1/100} is equivalent to {1/10)^2

and so we have:

          1                      1

  (------------)^(1/x) = -------   (we are to find x)

     10^2                    10

Note that 10 is the square root of 10^2, also the square root of 100.

So let's take the square root of 10^2.  We get 10.

Therefore, try x = 2 and see whether the given equation is true:

      1                      1

{---------)^(1/2)   =  ------

 100                     10

The square root of 1 is just 1.  The square root of 100 is 10.  

Therefore the above equation becomes

 1        1

----- = -----  and so  x = 2 is correct.

10      10

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Orbet used 24 square tiles to make a rectangle. The perimeter of the rectangle is 20 units. What would be the perimeters of the
Dmitriy789 [7]

Answer:

The perimeter of other rectangles are 50, 28, 22 units

The area of all possible rectangles are same and equals to 24 unit²

Step-by-step explanation:

Given - Orbet used 24 square tiles to make a rectangle. The perimeter of the rectangle is 20 units.

To find -  What would be the perimeters of the other rectangles Orbet could make using only these 24 tiles? How do the areas of the rectangles compare?

Proof -

We know that

Are of Rectangle = Length × Breadth

And Perimeter of Rectangle = 2 (Length + Breadth )

Now,

Given that,

Orbet used 24 square tiles

And perimeter of the rectangle made = 20

So,

Possible Length of rectangle = 6

Possible breadth of Rectangle = 4

Or Vice-versa.

Total number of Rectangles possible = 4

Possibilities are -  1 × 24, 2 × 12, 3 × 8, 4 × 6

Case I :

Length of rectangle = 1

Breadth of rectangle = 24

∴ Perimeter of rectangle = 2(1 + 24) = 2(25) = 50 units

Area of rectangle = 1 × 24 = 24 unit²

Case II :

Length of rectangle = 2

Breadth of rectangle = 12

∴ Perimeter of rectangle = 2(2 + 12) = 2(14) = 28 units

Area of rectangle = 2 × 12 = 24 unit²

Case III :

Length of rectangle = 3

Breadth of rectangle = 8

∴ Perimeter of rectangle = 2(3 + 8) = 2(11) = 22 units

Area of rectangle = 3 × 8 = 24 unit²

Case IV :

Length of rectangle = 4

Breadth of rectangle = 6

∴ Perimeter of rectangle = 2(4 + 6) = 2(10) = 20 units

Area of rectangle = 4 × 6 = 24 unit²

∴ we get

The perimeter of other rectangles are 50, 28, 22 units

The area of all possible rectangles are same and equals to 24 unit²

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Step-by-step explanation:

because 5•5=25 and 25-13=12

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