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nata0808 [166]
3 years ago
6

Just need the answers for these 3 questions please, and how to do them (:

Mathematics
2 answers:
Darya [45]3 years ago
6 0

Answer:

a) 7

b)64

c)2

Step-by-step explanation:

look at images

WITCHER [35]3 years ago
6 0

Answer:

x = 2

Step-by-step explanation:

The topic here is "fractional exponents."

Review:  2^3 = 8 (this is the cube of 2), and so the inverse function is

            8^(1/3) = 2    ("8 raised to the fractional exponent 1/3 is 2"

Question a)  49^(1/2) ("49 to the power 1/2") can be rewritten as

(7^2)^(1/2), which simplifies to 7^(2*1/2) = 7^1  =  7

Caution:  this is exponentiation, not division.  So 49^(1/2) does not equal 49/2.

Question b)     (     )^(1/3)  =  4

I would prefer to write this as x^(1/3) = 4 and set the goal of finding the value of the base, x.

Then x^(1/3) = 4   ("x raised to the power 1/3 is 4")

Let's elimiinate the fractional exponent on the left by cubing both sides of the equation:

{x^(1/3)}^3 = 4^3, or, after simplification,

x^1 = 64, or, in simplest form,

x = 64

Question c)

Notice that the base here is 1/100

and that the square root of 1 is 1 and that of 100 is 10.

Therefore, the given

{1/100} is equivalent to {1/10)^2

and so we have:

          1                      1

  (------------)^(1/x) = -------   (we are to find x)

     10^2                    10

Note that 10 is the square root of 10^2, also the square root of 100.

So let's take the square root of 10^2.  We get 10.

Therefore, try x = 2 and see whether the given equation is true:

      1                      1

{---------)^(1/2)   =  ------

 100                     10

The square root of 1 is just 1.  The square root of 100 is 10.  

Therefore the above equation becomes

 1        1

----- = -----  and so  x = 2 is correct.

10      10

You might be interested in
80 is ⅒ of ____. <br><br><br><br><br> HELP ME
Snowcat [4.5K]

Answer:

800

Step-by-step explanation:

If you multiply 1 tenth by 80 you will get 800 over 1.

800/1

800/1 = 800.

8 0
3 years ago
Write an equation of a line perpendicular to the line y = -1/5x -3 and goes through the point (6,2), then use Point- Slope form
agasfer [191]

Answer:

The equation of the line would be y = 5x - 28

Step-by-step explanation:

First, we need to know that perpendicular lines have opposite and reciprocal slopes. Give that information, we know that the new line will be the reciprocal and opposite of -1/5. This would be 5. Now that we have that information, we can use it along with a point to fill in the point-slope form of the equation.

y - y1 = m(x - x1)

y - 2 = 5(x - 6)

Then we must solve for y.

y - 2 = 5(x - 6)

y - 2 = 5x - 30

y = 5x - 28

7 0
3 years ago
Can someone please take me step by step to find x?
Aleksandr [31]
-(7x + 4)- 2x + 2 = 52

Distribute the negative sign:
-7x -4 - 2x + 2 = 52

Combine like terms:
-9x - 2 = 52

Add 2 to both sides:
-9x = 54

Divide by -9:
x = -6

Answer: x = -6
8 0
3 years ago
Read 2 more answers
Question 1,2, and 3 how do i factor those? Can you show the work and explain how?
DiKsa [7]

1: 3n^{2}+9n+6

notice that each part is divisible by 3

3n^{2} ÷ 3 = n^{2}

9n ÷ 3 = 3n

6 ÷ 3 = 2

so it becomes 3(n^{2} +3n+2)

3n can be rewritten as 2n+n

-you want to rewrite it into two numbers that multiply to the number that's alone (in this case 2)

which would get you

3(n^{2} +2n+n+2)

Now that it's rewritten, you can factor out n + 2 from the equation.

<u><em>the answer is </em></u>

3(n+2)(n+1)

And you can check that by multiplying (n+2)(n+1) which is n^{2} +2n+n+2 and then each of those by 3, which is 3n^{2} +6n+3n+6 or 3n^{2}+9n+6, our origional equation

2: 28+x^{2} -11x

So I rewrote this as x^{2} -11x+28 (it's the same thing, just reordered using the commutative property)

now -11x can be rewritten as -4x-7x

(remember, the two numbers should multiply to equal 28, which is our constant.)

x^{2} -4x-7x+28

now we can factor out x from the first expression and -7 from the second

x(x-4)-7(x-4)

and lastly you factor out x-4,

<u><em>which would give you</em></u>

(x-4)(x-7)

Make sure to check your work and make sure it multiplies to x^{2} -11x+28

3: 9x^{2} -12x+4

The first thing I notice when looking at this problem is that both 9 and 4 are perfect squares. Not only that, but they are the squares of 2 and 3, which are products of -12

So if you rewrite 9 as 3^{2} and 4 as 2^{2}, the equation becomes

3^{2} x^{2} -12x+2^{2}

now that 3^{2} x^{2} is ugly so it can be turned into (3x)^{2}

and -12x can be rewritten as -2*3x*2

so our equation now looks like (3x)^2-2*3x*2+2^{2}

There's a rule that says a^{2} -2ab+b^{2} = (a-b)^{2}

In our case, a=3x and b=2

<u><em>so the final answer is</em></u>

(3x-2)^2

5 0
2 years ago
The nth term of a sequence is 3n + 2
gavmur [86]

Answer:

see explanation

Step-by-step explanation:

To calculate the first 3 terms substitute n = 1, 2, 3 into the n th term rule

a_{1} = (3 × 1) + 2 = 3 + 2 = 5

a_{2} = (3 × 2) + 2 = 6 + 2 = 8

a_{3} = (3 × 3) + 2 = 9 + 2 = 11

------------------------------------------------------------------

substitute n = 10 into the n th term rule

a_{10} = (3 × 10) + 2 = 30 + 2 = 32

3 0
3 years ago
Read 2 more answers
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