I believe the answer is 32 models of 100
Answer:
6
Step-by-step explanation:
Label them as variables
A, B, and C
Now try and list them
ABC
ACB
BAC
BCA
CAB
CBA
There should be 6
The more mathematical way is using factorials
So you would do 3! which is 3*2*1
This also gives you 6
Answer:
x = 4
Step-by-step explanation:
This is special right triangles
For the triangle on the bottom, the shorter leg is x, the longer leg is x * √3, and the hypotenuse is x *2. This means that the shorter leg is 2 since you the longer leg is that side multiplied by √3. The hypotenuse is x *2, which is 2 * 2 which equals 4.
Now we have one side of the bigger triangle. This triangle is a 45-45-90 triangle, and the rule is that the two legs are x, and the hypotenuse is x *2. Since we found a leg and not the hypotenuse of the bigger triangle, and the two legs are congruent, that means x is 4.
Answer: Line AC = 24 units and line BC = 12 units.
Step-by-step explanation: Please refer to the diagram attached for more details.
The right angled triangle ABC has been drawn with angle A measuring 30 degrees and line AB measuring 12√3. To calculate the other two unknown sides AC labelled b, and BC labelled a, we shall use the trigonometric ratios. However, in this scenario, we shall apply the special values of each trigonometric ratio. These are shown in the box on the top right in the picture. The proof is given in the second right angled triangle at the bottom part of the attached picture.
Assume an equilateral triangle with lengths 2 units on all sides and 60 degrees at all angles. Drawing a line perpendicular to the bottom line would divide the top angle into two equal halves (30 degrees each), and the bottom line also would be divided into two equal halves (1 unit each). So the hypotenuse will measure 2 units and the line at the base would measure 1 unit. By using the Pythagoras' theorem, we derive the third side to be √3 <u>(that is x² = 2² - 1², and then x² = 4 - 1, and then x² = 3 and finally x = √3).</u>
Therefore, in triangle ABC, using angle 30 as the reference angle, to calculate side AC;
Cos 30 = Adjacent/Hypotenuse
Cos 30 = (12√3)/b
b = (12√3)/Cos 30
Where Cos 30 is √3/2
b = (12√3)/√3/2
b = (12√3) * 2/√3
b = 12 * 2
b = 24
To calculate side BC;
Tan 30 = Opposite/Adjacent
Tan 30 = a/(12√3)
Tan 30 * 12√3 = a
Where Tan 30 = 1/√3
(1/√3) * 12√3 = a
12 = a
Therefore, the missing lengths in the right triangle are
AC = 24 units and BC = 12 units
4/6 per hour or 2/3 per hour