Answer:
Step-by-step explanation:
Answer is 5 candies.
$25 is her total amount so you need to subtract the $8 that she paid for her ticket with.
The answer to that subtraction is $17.
With $17, you divide by $3.25 (price of candy) to get the number 5.2. Except, you can't buy a small bit of a candy, so you would be able to buy 5 in total.
Answer:
![\large\boxed{y=-\dfrac{4}{3}x-6}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7By%3D-%5Cdfrac%7B4%7D%7B3%7Dx-6%7D)
Step-by-step explanation:
The slope-intercept form of an equation of a line:
![y=mx+b[/te]xm - slopeb - y-interceptParallel line have the same slope. Therefore the equation of the line parallel to given line is:[tex]y=-\dfrac{4}{3}x+11\to m=-\dfrac{4}{3}\\\\y=-\dfrac{4}{3}x+b](https://tex.z-dn.net/?f=y%3Dmx%2Bb%5B%2Fte%5Dx%3C%2Fp%3E%3Cp%3E%3Cem%3E%3Cstrong%3Em%3C%2Fstrong%3E%3C%2Fem%3E%3Cem%3E%20-%20slope%3C%2Fem%3E%3C%2Fp%3E%3Cp%3E%3Cem%3E%3Cstrong%3Eb%3C%2Fstrong%3E%3C%2Fem%3E%3Cem%3E%20-%20y-intercept%3C%2Fem%3E%3C%2Fp%3E%3Cp%3EParallel%20line%20have%20the%20same%20slope.%20Therefore%20the%20equation%20of%20the%20line%20parallel%20to%20given%20line%20is%3A%3C%2Fp%3E%3Cp%3E%5Btex%5Dy%3D-%5Cdfrac%7B4%7D%7B3%7Dx%2B11%5Cto%20m%3D-%5Cdfrac%7B4%7D%7B3%7D%5C%5C%5C%5Cy%3D-%5Cdfrac%7B4%7D%7B3%7Dx%2Bb)
Put the coordinates of the given point (-6, 2) to the equation:
![2=-\dfrac{4}{3\!\!\!\!\diagup_1}(-6\!\!\!\!\diagup^2)+b](https://tex.z-dn.net/?f=2%3D-%5Cdfrac%7B4%7D%7B3%5C%21%5C%21%5C%21%5C%21%5Cdiagup_1%7D%28-6%5C%21%5C%21%5C%21%5C%21%5Cdiagup%5E2%29%2Bb)
![2=(4)(2)+b](https://tex.z-dn.net/?f=2%3D%284%29%282%29%2Bb)
<em>subtract 8 from both sides</em>
![-6=b\to b=-6](https://tex.z-dn.net/?f=-6%3Db%5Cto%20b%3D-6)
Finally:
![y=-\dfrac{4}{3}x-6](https://tex.z-dn.net/?f=y%3D-%5Cdfrac%7B4%7D%7B3%7Dx-6)
Answer:
speed for the slower automobile = 70
speed for the faster automobile = 80
Step-by-step explanation:
Speed of slower automobile = s and time taken by the slower automobile = t
Speed for faster automobile = s + 10 and time taken by the faster automobile = t -1
D = s*t
<em>For the slower automobile </em>
560 = st
<em>For the faster automobile</em>
560 = (s +10)(t-1)
560 = st - s + 10t -10
<em>Remember st = 560</em>
560 = 560 - s + 10(560/s) -10
560-560 +10 = -s + 5600/s
10 = -s + 5600/s
10s = -s² + 5600
s² + 10s - 5600 = 0
s = (-b ±(√b²-4ac))/2a
s = (-10±√(10² - 4(1)(-5600)))/2
s =(-10 ±√22500)/2
s= (-10+150)/2 or (-10 -150)/2
s=70 or -80
therefore speed for the slower automobile = 70
and speed for the faster automobile = 80
Hello :
<span>y²-2y=-9/2
(y²-2y +1) -1 = -9/2
(y-1)² = -7/2
in : R no solutions
in : C two solutions
y-1 =-(</span><span>√</span>7/2)i or y-1 = (√<span>7/2)i
y = 1 -(</span>√7/2)i or y = 1+(√<span>7/2) i because : -7/2 =(7/2)i²... i² = -1
</span>