The vertex form:

(h,k) - the coordinates of the vertex

The coordinates of the vertex are
(-4,13).
V = x/t = 4.5 mil / 3 h = 1.5 mph
Since, v = 1.5 mph (or we can say that v is constant), distance and time vary directly and the constant of variation is 1.5 mph.
A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
Answer:
The answer is 0.5, or 1/2.
3/12 ÷ 6/12 = 1/2
Hope this helps!
Answer:
Step-by-step explanation:
We have given a parallelogram ABCD.
For a parallelogram,
Opposite pair of sides are parallel to each other.
i.e AD is parallel to BC and AB is parallel to CD.
From the attached figure,
∡1 = ∡4 and ∡2 = ∡3 {If two parallel lines cut by a transversal line then alternate interior angles are congruent }
Next, AC ≅ AC {Reflexive identity}
hence, ΔABC ≅ ΔCDA , By Angle-Side-Angle(ASA) congruent property of triangle.
Therefore, AB = CD and AD = BC {Proved}