Answer:
Step-by-step explanation:
Answer:
36years
Step-by-step explanation:
Let charity present age be x
Charity daughter present age be y
Charity husband present age be z
If the sum of their ages ten years to come is 117, then;
10+x+10+y+10+z = 117
30+x+y+z = 117
x+y+z = 87 ... 1
If charity is four times as old as her daughter, then;
x = 4y
y = x/4 ... 2
If she is also six years younger than her husband, then;
x = z- 6
z = x+6 .. 3
Substitute 2 and 3 into 1;
x + x/4 + (x+6) = 87
Multiply through by 4
4x + x + 4(x+6) = 4(87)
5x+4x+24 = 348
9x = 348 - 24
9x = 324
x = 324/9
x = 36
hence Charity is 36years old today
Middle option.
<span>(x + 1 ≤ 1) ∩ (x + 1 ≥ 1)
If you work both sides separately you get
</span>(x ≤ 0) ∩ (x ≥ 0)
<span>
which reduces nicely to
</span><span>{x | x = 0}</span>
My best Guess is
1.282 for upper . , -1.282 for lower.
Hope this Helps
-Dante
