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2 years ago

6

A function is created to represent the height above sea level of a mountain climber every hour. What restrictions would be made

to the range?

1 answer:

matrenka [14]2 years ago

4 0

I believe this can help.

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Avicenna, a major insurance company, offers five-year life insurance policies to -65 year-olds. If the holder of one of these po

Alecsey [184]

Answer:

The question is about the least amount to charge each policyholder as premium

The least premium is $484

Step-by-step explanation:

The least amount of premium to charge for this policy is the sum of the expected values of outcome of both instances of policyholder dying before the age of 70 and living after the age of 70 years

expected value of dying before 70 years=payout*probability=$24,200*2%=$484

Expected of living after 70=payout*probability=$0*98%=$0

sum of expected values=$484+$0=$484

Note that payout is nil if policyholder lives beyond 70 years

The premium of $573 means that a profit of $89 is recorded

5 0

3 years ago

The average monthly rent for a? 1000-sq-ft apartment in a major metropolitan area from 1998 through 2005 can be approximated by

Lunna [17]

Answer:

t = 1.107

Step-by-step explanation:

Finding the solution using derivatives involves finding the lower zero of the quadratic that is the second derivative of the given function. That second derivative will be ...

f''(t) = 12(1.6714)t^2 -6(22.45)t +2(62.27)

= 20.0568t^2 -134.7t +124.54

= 20.0568(t -3.35796)² -101.619 . . . . rewrite to vertex form

Then f''(t) = 0 when ...

t ≈ 3.35796 -√(101.619/20.0568) ≈ 1.10706

__

The solution is perhaps more easily found using a graphing calculator to find the peak of the first derivative. (See attached.) It tells us ...

t ≈ 1.107

1.1 years after the beginning of 1998 is about 1.2 months into 1999.

Rents were increasing most rapidly in early February of 1999.

8 0

2 years ago

Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat

nirvana33 [79]

Answer:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

$\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}$

And solving for $\frac{dh}{dt}$ we got:

$\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}$

We need to convert the rate given into m^3/min and we got:

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

5 0

3 years ago

Write an essay about your learning on how you solve problems involving integers. (5 points). Take a photo of your answer. (To th

olga55 [171]

Answer:

to use integers for certain problems and equation on math, i can also use it for future use in life in case i need it, Its very helpful to learn since it isnt that complicated nor hard, its just a good skill to keep in mind as a student.

4 0

3 years ago

What is the average rate of change for this quadratic function for the interval from x = 0 to x = 2?

andre [41]

Answer is b hope this helps

6 0

3 years ago