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eimsori [14]
2 years ago
5

A 60.0 kg soccer player kicks a 0.4000 kg stationary soccer ball with 6.25 N of force. How fast does the soccer ball accelerate,

assuming that no friction acts on the ball?
a)2.50 m/s2
b)3.84 m/s2
c)15.6 m/s2
d)97.7 m/s2
Physics
1 answer:
frozen [14]2 years ago
8 0
F = ma
6.25 N = 0.4 kg · a
a = (6.25/0.4) m/s²      since N=kg·m/s²
a = 15.625 m/s² 

The answer is c) 15.6 m/s²
(Note that the mass of the soccer player is irrelevant.)
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Taya2010 [7]

Incomplete question as number of moles and length is missing.So I have assumed 3 moles and length of 0.300 m.So the complete question is here:

Three moles of an ideal gas are in a rigid cubical box with sides of length 0.300 m.What is the force that the gas exerts on each of the six sides of the box when the gas temperature is 20.0∘C?

Answer:

The Force act on each side is 2.43×10⁴N

Explanation:

Given data

n=3 mol

L=0.3 m

Temperature=20.0°C=293 K

To find

Force F

Solution

To get force act on each side it would employ by

F=P.A

Where P is pressure

A is Area

First we need to find pressure by applying ideal gas law

So

P.V=nRT\\P=\frac{nRT}{V}\\ P=\frac{(3mol)(8.315J/mol)(293K)}{(0.3m*0.3m*0.3m)}\\P=27.069*10^{4}Pa

So The Force is given as:

F=P.A\\F=(27.069*10^{4} )(0.3m*0.3m)\\F=2.43*10^{4}N

The Force act on each side is 2.43×10⁴N

3 0
3 years ago
A bike accelerates uniformly(from rest to a speed of 7 m/s over a distance of 40 m. Determine
marshall27 [118]

Answer:

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Explanation:

The bike's acceleration can be found by using the following suvat equation:

v^2-u^2=2as

where

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u is the initial velocity

a is the acceleration

s is the distance covered

For the bike in the problem,

u = 0

v = 7 m/s

d = 40 m

Solving the equation for a, we find the acceleration:

a=\frac{v^2-u^2}{2s}=\frac{7^2-0}{2(40)}=0.61 m/s^2

3 0
3 years ago
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kramer

Answer:

through direct contact

Explanation:

took the test!

3 0
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Answer:

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Explanation:

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\frac{x}{D}=\frac{1.22\lambda }{d}

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thus applying values we get

D=\frac{dx}{1.22\lambda }

\therefore D=\frac{0.633\times 4.61\times 10^{-3}}{1.22\times 547\times 10^{-9}}\\\\D=4372.77m\\=4.372km

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Have a nice day
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