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Kay [80]
3 years ago
13

Which system of equations has exactly one solution?

Mathematics
2 answers:
Cerrena [4.2K]3 years ago
5 0

Answer:

2x+y = 3

5x-y= 11

has exactly one solution

Step-by-step explanation:

Hope this Helped :)

Hunter-Best [27]3 years ago
4 0
If you put them in desmos online it works
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Evaluate 4b-3c-7 for b=4 and c=1
Alex
The answer is 8

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4 0
3 years ago
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PLEASE HELP!!! PLATO ALGEBRA 2
andrey2020 [161]

Answer:

(gof) (4) = 9

Hence, option A is true.

Step-by-step explanation:

f(x)=-x³

g(x)=|1/8x -1|

(gof) (4) = g{f(4)}

First wee need to determine f(4)

f(4)=-(4)³

    = -64

so

  (gof) (4) = g{f(4)} = g(-64)

                             =  \left|\frac{1}{8}\left(-64\right)-1\right|

                             =\left|-\frac{1}{8}\cdot \:64-1\right|

                             =\left|-8-1\right|

                             =\left|-9\right|

\mathrm{Apply\:absolute\:rule}:\quad \left|-a\right|=a

                             =9        

Thus,

(gof) (4) = 9

Hence, option A is true.

8 0
2 years ago
Select the correct answer.
Sonbull [250]

Answer:

B.

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4 0
2 years ago
A jar of salsa costs $0.95. Neha bought 9 jars of salsa. How much did Neha spend in all? <br><br> $
olga2289 [7]

Answer:

$8.55

Step-by-step explanation:

$0.95 x 9 jars = $8.55

For every jar Neha buys, she spends $0.95, and buying 9 jars in total, she pays $8.55 in total.

5 0
3 years ago
Read 2 more answers
A is a 4x4 matrix and A^2 + 4A - 5I = 0. If det(A+2I)&gt;0, enter det(A+2I)
maw [93]
\mathbf A^2+4\mathbf A-5\mathbf I=0
\implies\mathbf A^2+4\mathbf A+4\mathbf I=(\mathbf A+2\mathbf I)^2=9\mathbf I
\implies\det\bigg((\mathbf A+2\mathbf I)^2\bigg)=\det(9\mathbf I)
\implies\det(\mathbf A+2\mathbf I)^2=9^4\det\mathbf I
\implies\det(\mathbf A+2\mathbf I)=\pm\sqrt{9^4}
\implies\det(\mathbf A+2\mathbf I)=9^2=81

where we take the positive root because we're told that the determinant is positive.
5 0
3 years ago
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