3.5 3.4 3.3 3.2 3.1 3 -5.5 -1 -2
Answer:
C
Step-by-step explanation:
0 = 8 is a false statement which means the system has no solutions
She used the associative property which should only be used with positive numbers (sorry if it isn't the answer you're looking for)
A good place to start is to set 
to y. That would mean we are looking for 
to be an integer. Clearly, 
, because if y were greater the part under the radical would be a negative, making the radical an imaginary number, not an integer. Also note that since 
is a radical, it only outputs values from ![[0,\infty]](https://tex.z-dn.net/?f=%20%5B0%2C%5Cinfty%5D%20)
, which means y is on the closed interval: ![[0,120]](https://tex.z-dn.net/?f=%20%5B0%2C120%5D%20)
.
With that, we don't really have to consider y anymore, since we know the interval that is on.
Now, we don't even have to find the x values. Note that only 11 perfect squares lie on the interval , which means there are at most 11 numbers that x can be which make the radical an integer. All of the perfect squares are easily constructed. We can say that if k is an arbitrary integer between 0 and 11 then:
Which is strictly positive so we know for sure that all 11 numbers on the closed interval will yield a valid x that makes the radical an integer.
Answer:
y= (-3x +14.50) / 8
Step-by-step explanation:
Isolate the 8y
Subtract 3x from both sides
8y = -3x + 14.50
Then, isolate the left to only y
y= (-3x +14.50) / 8
