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Kay [80]
3 years ago
13

Which system of equations has exactly one solution?

Mathematics
2 answers:
Cerrena [4.2K]3 years ago
5 0

Answer:

2x+y = 3

5x-y= 11

has exactly one solution

Step-by-step explanation:

Hope this Helped :)

Hunter-Best [27]3 years ago
4 0
If you put them in desmos online it works
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<img src="https://tex.z-dn.net/?f=%28-3x%5E2y%29%5E%7B4%7D" id="TexFormula1" title="(-3x^2y)^{4}" alt="(-3x^2y)^{4}" align="absm
Valentin [98]

Answer:

errr polynomials ahaha

so basically we can multiply the power outside of the parantheses with the exponents on the inside:

so

-3x^{2*4} y^{1*4}

this will give us:

-3x^8y^4

we also unfortunately, have to use the power on the coefficient -3 as well  and we cant just MULTIPLY -3 by 4, we are going to have to multiply -3 with -3 4 TIMES(anytime we see a coefficient we MUST multiply the coefficient by itself according to the number outside of the parantheses)

so:

-3*-3*-3*-3=81

final expression

81x^{8}y^{4}

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Step-by-step explanation:

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