Answer:
num = int(input("enter a number:"))
print(num * 8)
Explanation:
num is just a variable could be named anything you want.
if code was like this num = input("enter a number:")
and do a print(num * 8)
we get an error because whatever the user puts in input comes out a string.
we cast int() around our input() function to convert from string to integer.
therefore: num = int(input("enter a number:"))
will allow us to do print(num * 8)
Answer:
Following are the code to the given question:
#include <iostream>//header file
using namespace std;
int main()//main method
{
int r=26,x,y;//defining integer variable
char c;//defining a character variable
for(x= 1; y<= r; x++)//using for loop for count value
{
for(y= 1; y<= x; y++)//using for loop to convert value in triangle
{
c=(char)(y+64);//convert value into character
cout << c;//print character value
}
cout << "\n";//use print method for line break
}
return 0;
}
Output:
Please find the attachment file.
Explanation:
In this code, three integer variable "x,y, and r", and one character variable "c" is declared, that is used in the nested for loop, in the first for loop it counts the character value and in the next for loop, it converts the value into a triangle and uses the char variable to print its character value.
Answer:
Probability Distribution={(A, 4/7), (B, 2/7), (C, 1/7)}
H(X)=5.4224 bits per symb
H(X|Y="not C")=0.54902 bits per symb
Explanation:
P(B)=2P(C)
P(A)=2P(B)
But
P(A)+P(B)+P(C)=1
4P(C)+2P(C)+P(C)=1
P(C)=1/7
Then
P(A)=4/7
P(B)=2/7
Probability Distribution={(A, 4/7), (B, 2/7), (C, 1/7)}
iii
If X={A,B,C}
and P(Xi)={4/7,2/7,1/7}
where Id =logarithm to base 2
Entropy, H(X)=-{P(A) Id P(A) +P(B) Id P(B) + P(C) Id P(C)}
=-{(1/7)Id1/7 +(2/7)Id(2/7) +(4/7)Id(4/7)}
=5.4224 bits per symb
if P(C) =0
P(A)=2P(B)
P(B)=1/3
P(A)=2/3
H(X|Y="not C")= -(1/3)Id(I/3) -(2/3)Id(2/3)
=0.54902 bits per symb
An alternative to hexadecimal notation for representing bit patterns is dotted decimal notation in which each byte in the pattern is represented by its base ten equivalent. In turn, these byte representations are separated by periods. For example, 12.5 represents the pattern 0000110000000101 (the byte00001100 is represented by 12, and 00000101 is represented by 5), and the pattern 100010000001000000000111 is represented by 136.16.7. Represent each of the following bit patterns in dotted decimal notation,
a. 0000111100001111 b. 001100110000000010000000c. 0000101010100000
Answer:
D. The Active Directory Users and Computers
Explanation:
The Active Directory Users and Computers (ADUC) is one of the many tools used to administer the Active Directory and it is the most common tool that Windows admins use on the domain controller. It provides most of the admins functions such as
i. resetting of password
ii. unlocking users
iii. delegating of permissions to users to manage group policy
iv. managing Active Directory objects - users, computers, contacts, groups - and their attributes.
Other tools are Active Directory Component Services (allows to manage component services), Active Directory Domains and Trusts (allows to manage trusts between forests and domains), Active Directory Administrative Center (allows to manage password policies and even get the history of PowerShell logs).
<em>Hope this helps!</em>
