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lara [203]
3 years ago
5

A retanglular athletic field has an area of 40x2+190x-50. The width of the field is 8x-2. What is the length of the athletic fie

ld?
Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
4 0
Length = Area/Width
Length = <span>40x2+190x-50 / 8x - 2
</span>Length = 10(4x2+19x-5) / 2(4x - 1)
Length = 5(4x2+19x-5) / (4x - 1)
Length = 20x2 + 95x - 25 / 4x - 5
Length = 5x + 25
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Describe and correct the error in finding the solution of the equation 2x=6x
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The area of parallelogram WXYZ is approximately 45 square units.
neonofarm [45]

Answer:

Option (4)

Step-by-step explanation:

Area of a triangle = \frac{1}{2} (a.b.\text{Sin}\theta)

Where a and b are the sides of a triangle and θ is the angle between the sides a and b.

By this rule,

Area of ΔWZY = \frac{1}{2}(\text{WZ}).(\text{YZ}).\text{Sin}(115)

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Perimeter of parallelogram WXYZ = WX + XY + YZ + WZ

                                                         = 9.93 + 10 + 9.93 + 10

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3 years ago
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