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valkas [14]
3 years ago
6

Copy the following code and run it. You should break it into the following 3 functions

Computers and Technology
1 answer:
Darya [45]3 years ago
6 0

Answer:

The solution code is as follows:

  1. #include <iostream>
  2. using namespace() std;
  3. const double PI = 3.14159;
  4. int getValidInput() {
  5.    int radius;
  6.    cout << "Type a -1 for radius to exit" << endl;
  7.    cout << "Enter the radius: ";
  8.    cin >> radius;
  9.    
  10.    while(radius < 0){
  11.        cout << "Type a -1 for radius to exit" << endl;
  12.        cout << "Enter the radius: ";
  13.        cin >> radius;
  14.    }
  15.    return radius;
  16. }
  17. double circleCalculations(int r){
  18.    
  19.        double circ = 2 * PI * r;
  20.        double area = PI * pow(r, 2);
  21.        return area;
  22. }
  23. void printResults(int r, double a){
  24.    
  25.    cout.setf(ios::fixed);
  26.    cout.precision(1);
  27.    cout << "A circle with radius " << r << " has a circumference of "
  28.    << circ << " and an area of " << a << endl << endl;  
  29. }
  30. int main()
  31. {
  32.    int radius;
  33.    double area;
  34.    double circ;
  35.    radius = getValidInput();
  36.    area = circleCalculations(radius);
  37.    printResults(radius, area);
  38. }

Explanation:

In this question, we can identify three main functional blocks from the original codes. We cut the block of codes that ask for user input radius and paste it into the new function getValidInput() (Line 6 - 9). However, we need to add the code in Line 11-15 to ensure only the radius with valid value will be returned.

Next, we can proceed to cut another block of code that calculate the circumference and area and paste it into function circleCalculations (Line 19 -24).

Next, we cut the code that display the radius and area and paste it to function printResults(Line 26-32).

At last, we call all the three functions in the main program (Line 39-41).

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Explanation

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Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

^nC_r = \frac{n!}{(n-r)!r!}

Where n = 15\ and\ r = 4

^{15}C_4 = \frac{15!}{(15-4)!4!}

^{15}C_4 = \frac{15!}{11!4!}

^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}

^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}

^{15}C_4 = \frac{32760}{24}

^{15}C_4 = 1365

<em>Hence, there are 1365 ways </em>

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

<em>From the given parameters; 3 out of 15 is detective;</em>

So;

p = 3/15

p = 0.2

q = 1 - p

q = 1 - 0.2

q = 0.8

Solving further using binomial;

(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

Probability =  ^nC_3pq^3

Substitute 4 for n, 0.2 for p and 0.8 for q

Probability =  ^4C_3 * 0.2 * 0.8^3

Probability =  \frac{4!}{3!1!} * 0.2 * 0.8^3

Probability = 4 * 0.2 * 0.8^3

Probability = 0.4096

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

<em>Probability that at least one is defective + Probability that at none is defective = 1</em>

Probability that none is defective is calculated as thus;

Probability =  q^n

Substitute 4 for n and 0.8 for q

Probability =  0.8^4

Probability = 0.4096

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

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