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Alika [10]
4 years ago
12

Wharts the differences between a dialation and a reduction in geometry?

Mathematics
1 answer:
Svetach [21]4 years ago
6 0
A dilation is when the figure is enlarged and a reduction is when the figure is reduced, smaller.
The scale factor for dilation is > 1 and reduction >0,<1
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Please Help Me !!!!!!
son4ous [18]
1.\\(4x^2+15x-3)-(-3x^2+5)\\=4x^2+15x-3+3x^2-5\\=7x^2+15x-8\leftarrow A.


2.\\-3f^2+4f-3+8f^2+7f+1\\=5f^2+11f-2\leftarrow C.


3.\\(2x^2+6x+1)+(-7x^2+2x-3)\\=2x^2+6x+1-7x^2+2x-3\\=-5x^2+8x-2\leftarrow B.


4.\\4x^2+3x-3\\\{4;\ 3;-3\}


5.\\6x^4+3x^3-2x^2+15x-14\\\{6;\ 3;-2;\ 15;-14\}\to5\leftarrow A.


6.\\-7x-5x^2+5\\\{-7\}\leftarrow D.


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I want help its urgent!!! <br><br>(iv), (v), (vi) Questions​
Artist 52 [7]

Solution:

iv) Given equation: x^{2} - y^{2} - 4x - 2y + 3

Since we are given two variables, we need to split the original expression into two quadratic expressions as

x^{2} - 4x + 4 - y^{2} - 2y - 1

Factoring x first:

x^{2} - 4x + 4 = x^{2} - 2x - 2x + 4

= x (x - 2) - 2 (x-2)

= (x-2)(x-2)

= (x-2)^{2}

Factoring y now:

-y^{2} - 2y - 1 = -1(y^{2} + 2y + 1)

= -1(y^{2} + y + y + 1)

= -1[ y(y+1) + 1(y+1)]

= -1 [(y+1)(y+1)]

= (y+1)(-y-1)

Therefore, the original expression becomes

(x-2)^{2}+(y+1)(-y-1)\\or \\(x-2)(x-2) + (y+1)(-y-1)

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3 years ago
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NeX [460]

Answer:

I got 0.00001693508 is that one of your answers?

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Paha777 [63]

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