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denis23 [38]
3 years ago
10

Which law relates temperature, pressure, volume, and the number of moles of a gas under perfect conditions? Boyle's law Charles'

s, law ideal, gas law, combined gas law

Chemistry
2 answers:
olya-2409 [2.1K]3 years ago
8 0

Answer : The correct option is, Combined gas law.

Explanation :

There are four gas's law which are :

  • Boyle's Law : It states that the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and the number of moles of gas.

         P\propto \frac{1}{V}

  • Charles' Law : It states that the volume of the gas is directly proportional to the temperature of the gas at constant pressure and the number of moles of the gas.

         V\propto T

  • Gay-Lussac's Law : It states that the pressure of the gas is directly proportional to the temperature of the gas at constant volume and the number of moles of gas.

         P\propto T

  • Avogadro's Law : It states that the volume of the gas is directly proportional to the number of moles of the gas at constant pressure and temperature of the gas.

         V\propto n

The combined gas law is formed by the combination of these four laws.

The combined gas law equation is,

PV\propto nT

For removal of the proportionality we are added the constant term 'R' which is a gas constant.

PV=nRT

Hence, combined gas law relates temperature, pressure, volume, and the number of moles of a gas under perfect conditions.

Triss [41]3 years ago
6 0
<span>The correct answer is ideal gas law.

when the ideal gas law formula is:

 PV = nRT ,

when P is the pressure. 

V is the volume. 

and R is the ideal gas constant.

T is the temperature. 

and n is the number of moles.

So, this is the law which relates pressure, temperature, volume and number of moles . and this law state that 1 mole of an ideal gas will occupy a volume V = 22.4 L</span>
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In phosphide ion, the (-ide) indicates that the phosphide ion is the anion of phosphorous. So, we will have to add electrons.

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How many grams of KCl (s) has been produced from the thermal decomposition of KClO3 (s) that produced 50.0 mL of O2 (g) at 25 de
geniusboy [140]

Answer:

The mass is m_{KCl} =  0.102 \ g

Explanation:

From the question we are told that

   The volume of oxygen produced is  V_o = 50mL  = 50 *10^{-3} L

    The temperature is T = 25 ^oC = 25* 273 = 298 K

     The pressure is  P = 1.0\  atm

From the ideal gas law we have that

      PV =  nRT

Where R is the gas constant  with the value

         R =  0.08206 \ atm \cdot L /mol K

  n is the number of moles making it the subject of the formula

          n = \frac{PV}{RT}

Substituting values

          n = \frac{1 * (50 *10^{-3}) }{0.08206 * 298}

          n =  2.045 *10^{-3} \  mol

From the chemical equation

      one mole of  KClO_3 produces one mole of  kCl and   \frac{3}{2} of oxygen

       x mole of  KClO_3 produces x mole of  kCl and   2.045 *10^{-3} \  mol of oxygen

So    x = \frac{2.045 *10^{-3}}{\frac{3}{2} }

      x =  \frac{2}{3} * 2.045 *10^{-3}

      x =  1.363 *10^{-3} \ mol

Now the molar mass of  KCl is a constant with a value

           M_{KCl} = 74.55  g/mol

Now the mass of KCl is mathematically evaluated as

          m_{KCl} = x * M_{KCl}

Substituting values

          m_{KCl} = 1.363 *10^{-3} * 74.55

         m_{KCl} =  0.102 \ g

6 0
3 years ago
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