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yan [13]
4 years ago
6

Green light shines through a 100-mm-diameter hole and is observed on a screen.If the hole diameter is increased by 20%, does the

circular spot of light on the screen decrease in diameter, increase in diameter, or stay the same
Physics
1 answer:
Ede4ka [16]4 years ago
3 0

Answer:

For this case we can use the model given by:

W = \frac{K \lambda L}{D}

Where K is a constant and we can see W represent the spot of light and if D increases then W needs to decrease since the other variables \lambda , L remains constant.

Conclusion: The circular spot of light on the screen increase in diameter.

Explanation:

For this case we know that the diameter is:

D = 100 mm

And the hole diameter is increased by 20%, so the final diameter would be:

D_f = 1.2*100=120 mm

And for this case if we use concepts from the theory of rays we know that if the diameter of the hole gets bigger then the hole wuld increase.

For this case we can use the model given by:

W = \frac{K \lambda L}{D}

Where K is a constant and we can see W represent the spot of light and if D increases then W needs to decrease since the other variables \lambda , L remains constant.

Conclusion: The circular spot of light on the screen increase in diameter.

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A toy balloon has an internal pressure of 1.05 atm and a volume of 5.0 L. If the temperature where the balloon is released is 20
Marysya12 [62]

Answer:

Then volume of the balloon will increase to 7.11 L

Explanation:

Step 1:

Data obtained from the question. This includes:

Initial pressure (P1) = 1.05 atm

Initial volume (V1) = 5.0 L

Initial temperature (T1) = 20°C

Final pressure (P2) = 0.65 atm

Final temperature (T2) = –15°C

Final volume (V2) =?

Step 2:

Conversion of celsius temperature to Kelvin temperature. This is illustrated below

K = °C + 273

T1 = 20°C + 273 = 293K

T2 = –15°C + 273 = 258K

Step 3:

Determination of the final volume.

Applying the general gas equation P1V1/T1 = P2V2/T2, the final volume of the balloon can be obtained as follow:

P1V1/T1 = P2V2/T2

1.05 x 5/293 = 0.65 x V2/258

Cross multiply to express in linear form

293 x 0.65 x V2 = 1.05 x 5 x 258

Divide both side by 293 x 0.65

V2 = (1.05 x 5 x 258) / (293 x 0.65)

V2 = 7.11 L

Therefore, the volume of the balloon will increase to 7.11 L when the balloon rises to an altitude where the pressure is 0.65 atm and the temperature is –15° C

7 0
3 years ago
A set of data is collected for object in an inelastic collision, as recorded in the table.
TiliK225 [7]

Answer:

To identify the momentum of object 1, you must multiply mass (m) and velocity(v) to find momentum.

Object 1 has momentum of 8 kg. m/s before collision.

Object 1 has momentum of 0 kg. m/s before collision.

The combined mass after the collision had a total momentum of 8 kg. m/s.

Explanation:

Momentum of the object is given by,

Momentum = mass × velocity

For object 1:

Momentum = mass × velocity

Momentum = 2 × 4

Momentum = 8 kg. m/s

For object 2:

Momentum = mass × velocity

Momentum = 6 × 0

Momentum = 0 kg. m/s

For object 1 + object 2:

Momentum = mass × velocity

Momentum = 8 × 1

Momentum = 8 kg. m/s

To identify the momentum of object 1, you must multiply mass (m) and velocity(v) to find momentum.

Object 1 has momentum of 8 kg. m/s before collision.

Object 1 has momentum of 0 kg. m/s before collision.

The combined mass after the collision had a total momentum of 8 kg. m/s.


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4 years ago
Which of the following is a renewable source of energy?
STatiana [176]

Answer:

A. boi-gas

Explanation:

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3 years ago
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Calcula el peso de una mesaven la tierra cuya masa es de 60 kg
blsea [12.9K]

Answer:

W = 588 N

Explanation:

The given question is ,"calculate the weight of a table on the earth whose mass is 60 kg"

The mass of the table, m = 60 kg

We need to find the weight of a table on the earth.

The weight of an object is given by :

W = mg

Where

g is acceleration due to gravity

W = 60 kg × 9.8 m/s²

W = 588 N

Hence, the weight of the table is 588 N.

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Thank you for spreading awareness!


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