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kolezko [41]
4 years ago
12

Two billiard balls with the same mass undergo a perfectly elastic head-on collision. if one ball's initial speed was 2 m/s, and

the other's was 3.6 m/s in the opposite direction, what will be their speeds and directions after the collision
Physics
1 answer:
My name is Ann [436]4 years ago
6 0
<span>The ball with an initial velocity of 2 m/s rebounds at 3.6 m/s
 The ball with an initial velocity of 3.6 m/s rebounds at 2 m/s

   There are two principles involved here
 Conservation of momentum and conservation of energy.
  I'll use the following variables
 a0, a1 = velocity of ball a (before and after collision)
  b0, b1 = velocity of ball b (before and after collision)
 m = mass of each ball.

   For conservation of momentum, we can create this equation:
 m*a0 + m*b0 = m*a1 + m*b1
 divide both sides by m and we get:  
a0 + b0 = a1 + b1

   For conservation of energy, we can create this equation:
 0.5m(a0)^2 + 0.5m(b0)^2 = 0.5m(a1)^2 + 0.5m(b1)^2
 Once again, divide both sides by 0.5m to simplify
 a0^2 + b0^2 = a1^2 + b1^2

   Now let's get rid of a0 and b0 by assigned their initial values. a0 will be 2, and b0 will be -3.6 since it's moving in the opposite direction.
 a0 + b0 = a1 + b1
 2 - 3.6 = a1 + b1
 -1.6 = a1 + b1
 a1 + b1 = -1.6

   a0^2 + b0^2 = a1^2 + b1^2
 2^2 + -3.6^2 = a1^2 + b1^2
 4 + 12.96 = a1^2 + b1^2
 16.96 = a1^2 + b1^2
 a1^2 + b1^2 = 16.96

   The equation a1^2 + b1^2 = 16.96 describes a circle centered at the origin with a radius of sqrt(16.96). The equation a1 + b1 = -1.6 describes a line with slope -1 that intersects the circle at two points. Those points being (a1,b1) = (-3.6, 2) or (2, -3.6). This is not a surprise given the conservation of energy and momentum. We can't use the solution of (2, -3.6) since those were the initial values and that would imply the 2 billiard balls passing through each other which is physically impossible. So the correct solution is (-3.6, 2) which indicates that the ball going 2 m/s initially rebounds in the opposite direction at 3.6 m/s and the ball originally going 3.6 m/s rebounds in the opposite direction at 2 m/s.</span>
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Answer:

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Newton's second law for rotation

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I :  it is the moment of inertia of the body with respect to the axis of rotation (kg*m²)

α : It is angular acceleration. (rad/s²)

Kinematics of the wheel

Equation of circular motion uniformly accelerated :  

ωf = ω₀+ α*t  Formula (2)

Where:  

α : Angular acceleration (rad/s²)  

ω₀ : Initial angular speed ( rad/s)  

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Data  

ω₀ = 0

ωf = 1.2 rad/s

t = 2 s

Angular acceleration of the wheel  

We replace data in the formula (2):  

ωf = ω₀+ α*t

1.2= 0+ α*(2)

α*(2) = 1.2

α = 1.2 / 2

α = 0.6 rad/s²

Magnitude of the net torque (τ )

τ = F *R

Where:

F  = tangential force (N)

R  = radio (m)

τ = 80 N *0.12 m

τ = 9.6 N *m

Rotational inertia of the wheel

We replace data in the formula (1):

τ = I * α

9.6 = I *(0.6 )

I = 9.6 / (0.6 )

I = 16 kg*m²

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Why do windows have two panes of glass separated by a layer of air
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Answer:

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now we have

v_r = 215 - 155

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