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stiv31 [10]
3 years ago
12

In a single-slit diffraction experiment, a coherent light source illuminates a slit in a barrier, and the resulting pattern is p

rojected on a screen that is separated from the barrier by a distance which is very large as compared to the slit width and the wavelength of the light source. A student makes sketches of the resulting patterns. While the center of each bright or dark band is accurately represented, the shading is qualitative, and the choice of color may not reflect the wavelength of the light source. The distance from the barrier to the screen is 2.3 m, and the slit has width 7.3 μm.
A) What is the ratio of the slit width to the wavelength of the incident light?
B) What is the wavelength of the incident light, in nanometers?
C) If the screen is very wide, how many dark bands appear to one side of the central maximum?
Physics
1 answer:
UkoKoshka [18]3 years ago
4 0

Answer:

hsjdsdddwqdqwdd

Explanation:

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The resistanceless inductor is connected across the ac source whose voltage amplitude is 24.5 V and angular frequency is 850 rad
timurjin [86]

Answer:

Part A 2.88 A, PART B 28.82 mA PART C  0.288 mA

Explanation:

We have given angular frequency \omega =850rad/sec

Voltage source has an amplitude of 24.5 V, So V= 24.5 volt

Part A

We have given inductance L=10^{-2}H

So inductive reactance X_L=\omega L=850\times 10^{-2}=8.5ohm

So current i=\frac{V}{X_L}=\frac{24.5}{8.5}=2.8823A

Part B

We have given inductance L=1 H

So inductive reactance X_L=\omega L=850\times 1=850ohm

So current i=\frac{V}{X_L}=\frac{24.5}{850}=28.82mA

Part C

We have given inductance L=100 H

So inductive reactance X_L=\omega L=850\times 100=85000ohm

So current i=\frac{V}{X_L}=\frac{24.5}{85000}=0.288mA

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3 years ago
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zhuklara [117]
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4 years ago
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(I) A hiker determines the length of a lake by listening for the echo of her shout reflected by a cliff at the far end of the la
xxMikexx [17]

Answer:

425 m

Explanation:

From the question,

v = 2x/t.................... Equation 1

Where v = speed of sound in air, x = Length of the lake, t = time.

make x the subject of the equation

x = vt/2............... Equation 2

Given: t = 2.5 s

Constant: v = 340 m/s.

Substitute these values into equation 2

x = 340(2.5)/2

x = 425 m.

Hence the length of the lake is 425 m

4 0
4 years ago
Let’s say you have a cart of some mass and when pushed with 10N of force, the cart accelerates at 5.0 m/s/s. If you were to push
Korolek [52]

Answer:

a. The acceleration would increase.

Explanation:

because we know that

F=ma

m= mass and a= acceleration

so Mass is same for the cart in any situation that's why only acceleration could increase.

7 0
3 years ago
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A bird of mass 1.5 kg is flying at 8 m/s at a height of 50 m above the ground. What is its
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