Answer:
One way to find the least common multiple of two numbers is to first list the prime factors of each number. Then multiply each factor the greatest number of times it occurs in either number. If the same factor occurs more than once in both numbers, you multiply the factor the greatest number of times it occurs.
Step-by-step explanation:
X >- 5
-2x -4 < 3x +21
+4 +4
-2x < 3x +25
-3x -3x
-5x < +25
-5x/-5 25/-5
X > -5
Answer:
3n + 2
Step-by-step explanation:
-n+(-4)-(-4n)+6
= -n -4 +4n +6 [positive plus negative = negative; ∴ +(-4) = -4
=4n - n +6 - 4 negative plus negative = positive; ∴ -(-4n) = 4]
now subtract n from 4n and subtract 4 from 6
=3n + 2
Answer:
303
Step-by-step explanation:
So the equation to find a term is An=a1+(n-1)d
An represents the value of the number (n)
and n is the selective that you want
d is the difference between the first and second term which is 23-18=5, and you can see that adding 5 to the previous term gives the following term.
a1 is the first term in the sequence
so knowing all that now you can go back and inset all variables into the equation
An=18+(58-1)5
An=303
Hope that helps :)
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