For this problem, let's use the Planck's equation which is written below:
E = hv
where
E is the energy
h is Planck's constant equal to 6.626×10⁻³⁴ J·s
v is frequency
Solving for E,
E = (6.626×10⁻³⁴ J·s)(7.14×10¹⁴ s⁻¹)
<em>E = 4.73×10⁻¹⁹ J</em>
The answer is C) Collide. I took the test and this was the answer. Hope this helps.
A light microscope to see small things naked to the human eye
<span>The root mean square velocity of gas molecules as a function of temperature is (M is molecular weight):
v²rms = 3RT/M,
and kinetic energy is given by:
KE = ½Mv ²
We can make the substitution:
KE = ½M3RT/M, or
KE = (3/2)RT.
Notice the molecular weight variable is gone; that means the answer will be the same for F2, Cl2, and Br2:
KE = (3/2) (8.314 J/K*mole) (290 K) = 3617 J/mole.</span>
Answer:
NBr3 has a trigonal pyramidal geometry where the nitrogen atom is bonded to three bromine atoms and has one lone pairs. The individual bonds are polar, as bromine is less electronegative than nitrogen. The overall compound is also polar, as the dipoles do not cancel.
Explanation: