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podryga [215]
3 years ago
8

Hi there, I need help producing the aim and hypothesis for the question

Chemistry
1 answer:
svetlana [45]3 years ago
4 0

Answer:

in supernova gold can be turned into lead.

its practical to obtain gold from lead

hope this helps you☺️☺️

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I found a type of rock in the woods it's kinda rough black with some purple like a lavender purple and i can break it into piece
Vesna [10]
It could be a lump of coal.
Since you can break pieces off, maybe charcoal ... the real thing, not a "briquet".
Do your hands get all black when you handle it ?
5 0
4 years ago
In order to make 159 ml of a 0.135 M benzoic acid solution, what mass of benzoic acid (C7H6O2) is required?
STALIN [3.7K]

Answer:

Explanation:

159 mL of .135 M benzoic acid will contain

.159 x .135 = .021465 moles of benzoic acid.

Molecular weight of benzoic acid = 122 gm

grams of .021465 moles = 122 x .021465 = 2.6 grams .

So 2.6 grams of benzoic acid will be required .

8 0
3 years ago
Why is an atom electrically neutral​
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When an atom has an equal number of electrons and protons, it has an equal number of negative electric charges (the electrons) and positive electric charges (the protons). The total electric charge of the atom is therefore zero and the atom is said to be neutral
8 0
3 years ago
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How come when i drink red bull it doesn’t give me wings? help asap
harina [27]

Explanation:

Because it’s a energy drink but does have high sugar additives.

4 0
3 years ago
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If a gaseous sample contains 80.% N2 by volume, what is the solubility of N2 in water at 25°C and 1.0 atm (kH in H2O at 25°C = 7
Sedaia [141]

<u>Answer:</u> The solubility of nitrogen gas in the sample is 5.6\times 10^{-4}mol/L

<u>Explanation:</u>

We are given:

Volume percent of nitrogen gas = 80 %

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{N_2}=K_H\times p_{N_2}

where,

K_H = Henry's constant = 7.0\times 10^{-4}mol/L.atm

p_{N_2} = partial pressure of nitrogen gas = 1.0 atm

Putting values in above equation, we get:

C_{N_2}=7.0\times 10^{-4}mol/L.atm\times 1.0\\\\C_{N_2}=7.0\times 10^{-4}mol/L

Solubility of nitrogen gas in the sample = \frac{80}{100}\times 7.0\times 10^{-4}mol/=5.6\times 10^{-4}mol/L

Hence, the solubility of nitrogen gas in the sample is 5.6\times 10^{-4}mol/L

4 0
3 years ago
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