8.40 ml. I think that is right.
<h3><u>Answer;</u></h3>
<u> = 1319.45 Joules </u>
<h3><u>Explanation;</u></h3>
Kinetic energy is the energy possessed by a body in motion;
It is given by the formula; 1/2mv², where m is the mass of the body and v is the velocity.
mass = 89.5 kg and v =5.43 m/s
Therefore;
Kinetic energy = 1/2 × 89.5 × 5.43 ²
<u> = 1319.45 Joules </u>
<span>Rubidium and cesium have similar chemical properties because in the ground state the atoms of both elements each have one electron in the outermost shell. The correct option is A. The two elements belong to group one of the periodic table; all elements in this group have only one electron in their outmost shell which they easily give away to other elements during chemical reactions in order to attain octet structure.</span>
Answer:
4.415 g of FeSO₄
Explanation:
The balance chemical equation for given single replacement reaction is as follow;
Fe + H₂SO₄ → FeSO₄ + H₂
Data Given;
Volume = 650 mL = 0.65 L
Density at STP = 0.08988 g/L
Mass = Density × Volume = 0.08988 g/L × 0.65 L = 0.0584 g
Step 1: <u>Calculate Moles of H₂ as; </u>
Moles = Mass / M.Mass
Moles = 0.0584 g / 2.01 g/mol
Moles = 0.0290 mol of H₂
Step 2: <u>Find out moles of FeSO₄ as;</u>
According to balance chemical equation,
1 mole of H₂ is produced along with = 1 mole of FeSO₄
So,
0.0290 moles of H₂ will be produced along with = X moles of FeSO₄
Solving for X,
X = 0.0290 × 1 mol / 1 mol
X = 0.0290 moles of FeSO₄
Step 3: <u>Calculate mass of FeSO₄ as;</u>
Mass = Moles × M.Mass
Mass = 0.0290 mol × 151.90 g/mol
Mass = 4.415 g of FeSO₄
Answer:
We have to add 17.2 grams of aluminium bromide
Explanation:
Step 1: Data given
Molarity of the aluminum bromide solution = 0.215 M
Volume = 300 mL = 0.300 L
Molar mass aluminium bromide = 266.69 g/mol
Step 2: Calculate moles Aluminium bromide
moles AlBr3 = volume * molarity
Moles AlBr3 = 0.300 L * 0.215 M
Moles AlBR3 = 0.0645 moles
Step 3: Calculate mass aluminium bromide
Mass aluminium bromide = moles AlBr3 * molar mass AlBr3
Mass aluminium bromide = 0.0645 moles * 266.69 g/mol
Mass aluminium bromide = 17.2 grams
We have to add 17.2 grams of aluminium bromide