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bogdanovich [222]
1 year ago
13

What volume of oxygen in liters at STP wpuld be required for the combustion of 17.0 grams PH3?

Chemistry
1 answer:
Lynna [10]1 year ago
7 0

First, we need to state the chemical equation for the combustion of PH3

4PH3\text{ + 8O2 }\to\text{ P4O10 }+6H2O

And the mass of PH3 is 17.0 grams and we need to know the moles.

In the periodic table, the atomic mass of the P (phosphorus) is 31 and the atomic mass of the H (hydrogen) is 1.

So, you sum the mass of P to the mass of H multiplied by 3 and you obtain this:

\text{mole}cu\text{lar weight of PH3=31}\cdot1+1\cdot3=34\text{ g PH3/mol}

With this data, we can search the moles of PH3:

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<h3>What is pH?</h3>

The term pH, which originally stood for "potential of hydrogen" (or "power of hydrogen"), is used in chemistry to describe how acidic or basic an aqueous solution is. Lower pH values are summarized for acidic solutions (solutions with higher H+ ion concentrations) than for basic or alkaline solutions.

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