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bogdanovich [222]
9 months ago
13

What volume of oxygen in liters at STP wpuld be required for the combustion of 17.0 grams PH3?

Chemistry
1 answer:
Lynna [10]9 months ago
7 0

First, we need to state the chemical equation for the combustion of PH3

4PH3\text{ + 8O2 }\to\text{ P4O10 }+6H2O

And the mass of PH3 is 17.0 grams and we need to know the moles.

In the periodic table, the atomic mass of the P (phosphorus) is 31 and the atomic mass of the H (hydrogen) is 1.

So, you sum the mass of P to the mass of H multiplied by 3 and you obtain this:

\text{mole}cu\text{lar weight of PH3=31}\cdot1+1\cdot3=34\text{ g PH3/mol}

With this data, we can search the moles of PH3:

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