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3 years ago

Convert 45.5 mmHg into kPa

Chemistry

1 answer:

Karolina [17]3 years ago

8 0

Answer:

for anapproximate result , divide the pressure value by 7.501

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Magnetism is an example of a property of what?

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In the reaction: ch3cooh(aq) + nh2â(aq) ch3cooâ(aq) + nh3(aq), the conjugate acid-base pairs are:

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CH₃COOH-CH₃COO⁻ is a conjugate acid-base pair. NH₃-NH₂⁻ is another conjugate acid-base pair

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3 years ago

Two bulbs are connected by a stopcock. The large bulb, with a volume of 6.00 L, contains nitric oxide at a pressure of 0.700 atm

ivolga24 [154]

Answer:

$O_{2}$ and $NO_{2}$

Explanation:

For a given system at constant temperature, the number of moles of gas present in the system is proportional to the product of the system pressure and volume. Therefore, we have:

NO: 6 L * 0.7 atm = 4.2 L*atm

O: 1.5 L* 2.5 atm = 3.75 L*atm

For the given system based on a balanced chemical equation:

2.70 L*atm of nitric oxide reacts with (2.7/2) 1.35 L*atm of oxygen. This shows that there is more oxygen gas in the system than nitric oxide. Thus nitric oxide is the limiting reactant.

At the end of the experiment:

All the nitirc oxide has been used up, i.e. $P_{NO}$ = 0

For the product: 2.70 L*atm NO produced 2.70 L*atm $NO_{2}$

The total volume of the system after the stopcock is opened = 6+1.5 = 7.5 L

The partial pressure of $NO_{2}$ = (2.70 L*atm $NO_{2}$ ) / (7.5 L) = 0.36 atm $NO_{2}$

Similarly for oxygen gas:

3.75 L*atm - 1.35 L*atm = 2.40 L*atm oxygen gas remaining

Partial pressure of oxygen is:

2.40 L*atm / 7.5 L = 0.32 atm

Thus, the gases present at the end of the experiment are $O_{2}$ and $NO_{2}$

3 0

3 years ago

Consider the rate constants below. which would correspond to the highest order reaction? k = 8.79 x 102 ms–1 k = 4.46 x 10–1 m–1

Kipish [7]

When the order n of the reaction rate is determined by this formula:

rate = K * [A]^n

when we have the unit of rate M S^-1

and the unit of [A] M

So:

1- for k = 8.79 x 10^2 M S^-1 :

when the unit of K here is M S^-1

by substitution in rate formula:

M S^-1 = M S^-1 * M ^n

∴ M^n = 1

∴M^0 = 1

∴ this reaction rate is zero order reaction

2- when k = 4.46 x 10^-1 and has unit M-1 S-1:

by substitution in rate formula:

M S^-1 = M-1 S-1 * M^n

∴M^2 = M^n

∴n = 2 so this is the second order reaction

3- when K 2.35 x 10^6 and it's unit is S-1 :

So by substitution in rate formula:

M S^-1 = S^-1 * M^n

∴ M^n = M

∴ n = 1

So this is the first order reaction

4- when k = 1.88 x 10^-3 and its unit is M-2 S-1

by substitution in rate formula:

M S^-1 = M^-2 S^-1 * M^n

∴ M^n = M^3

∴ n = 3

∴ this is a third order reaction

from 1 & 2 & 3 & 4

so we can see that the correct answer is (4), K= 1.88 x 10^-3 M-2 S-1 is the highest order reaction.

3 0

3 years ago