1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nadusha1986 [10]
3 years ago
5

A hardware supplier manufacturers 3 kinds of clamps types AB &c production restrictions force it to make 10 more type C clam

ps in the total of the other types and 3 times as many tight be clamps as type a clamps the shot must produce 490 clamps per day how many of each time are made predict
Mathematics
1 answer:
hichkok12 [17]3 years ago
5 0

Answer:

Hardware supplier will manufacture 60 Type A clamps, 180 Type B clamps and 150 Type C clamps.

Step-by-step explanation:

Given:

Company produces 3 types of clamp

Type A

Type B

Type C

production restrictions force it to make 10 more type C clamps in the total of the other types

Hence We can say that Clamp C is equal to sum of Clamp A and Clamp and 10

framing in equation form we get;

C=A+B+10 \ \ \ \ \ equation \ 1

Also Given:

3 times as many Type B clamps as type A clamps

Hence we can say that Clamp B is equal to thrice of Clamp A.

B=3A \ \ \ \ equation\ 2

Also Given

Total Number of Clamps  = 490

Hence Total  Number of Clamps  is equal to sum of number of Clamps of Type A, Type B and Type C.

Framing in equation form we get;

A+B+C =490 \ \ \ \ equation \ 3

Substituting the equation 1 and Equation 2 in equation 3 we get

A+B+C=490\\\\A+3A+A+B+10=490\\\\A+3A+A+3A+10=490\\\\8A = 490-10\\\\8A=480\\\\A=\frac{480}{8}=60

Now Substituting the Value of A in equation 2 we get;

B=3A = 3\times60 =180

Now Substituting the values of A and B in equation 1 we get:

C=A+B+10 = 60+180+10= 250

Now checking the same we get;

A+B+C=490\\60+180+250=490\\490=490

Hence the Hardware supplier will manufacture 60 Type A clamps, 180 Type B clamps and 150 Type C clamps.

You might be interested in
What is the contrapositive of the statement below?
algol13

Answer:

B. -y = -x

Step-by-step explanation:

When the values on both sides of the equal sign are changed, it becomes a negative number.

6 0
2 years ago
I. Direction: Write the following statement as equations. Write your answers
Bingel [31]

Answer:

1. 4x - 29=11

2. (3x - 4) (2) = 46

3. 3/5x + 8 = 50

4. The difference of 51 and the sum of x and 5.

5. The product of 3 and y minus eight.

Step-by-step explanation:

4 0
3 years ago
What is the least common multiple of 420 and 196?
maks197457 [2]

2940. To find LCM, listing the multiples may help. Then you will easily be able to view them and circle when you find a common one. :)
4 0
3 years ago
Read 2 more answers
Carpeting costs $9.95 per yard. If Jamie buys 8 yards, how much will it cost him?
Hatshy [7]

Answer:

$79.6

Step-by-step explanation:

9.95 x 8 = 79.6

8 0
3 years ago
Find the area of the given figure.
marissa [1.9K]

84.6 km2 is the answer

6 0
3 years ago
Read 2 more answers
Other questions:
  • What’s the anwers ? Need help
    15·2 answers
  • The coordinates of the vertices of quadrilateral ABCD are A(-5, 1), B(-2,5), C(5, 3),
    13·2 answers
  • Solve the equation using square roots:<br> 2x^2-17=15
    11·1 answer
  • Solve the rational equation 8/x+1/5=3/x
    9·1 answer
  • A quadrilateral with two pairs of consecutive sides congruent and no opposite sides congruent is called a(n)
    8·1 answer
  • In many fast food restaurants, there is a strong correlation between a menu item's fat content (measured in grams) and its calor
    9·1 answer
  • Is the relationship a linear function?(0,-1), (1,5),(2,11),(3,17)
    11·1 answer
  • Factories fully 8x^2+6x
    10·2 answers
  • Find the area of a trapezium whose parallel sides are respectively 14cm and 4cm and distance between the parallel sides is 5cm.
    6·1 answer
  • The product of a number and 3 is the same as the sum of that number and 6
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!