Hey there :)
We have two equations:
3a + 2b = 7
2a + 2b = 9
We need to solve simultaneously to find the values of a and b
eq.1 3a + 2b = 7
eq.2 ( 2a + 2b = 9 ) x -1 ) multiply by -1 to cancel 2b
3a + 2b = 7
- 2a - 2b = -9 ( Add both together )
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a = - 2 Substitute the value you found for a in a in order to find b
3( - 2 ) + 2b = 7 2( - 2 ) + 2b = 9
- 6 + 2b = 7 OR - 4 + 2b = 9
2b = 13 2b = 13
b =
b =
899/7.....if u plug this into a calculator u will get 128.(and a bunch of decimal numbers).....but u have the whole number 128....so 128 x 7 = 896 + 3 = 899
so the answer to this problem is basically : 899/7 = 128 remainder 3
Answer: The answer would be 0=0 I think.
Step-by-step explanation:
Answer:
5/2, 5/2, -3= (5/2)(2)+b, -8, y=(5/2)x-8
Step-by-step explanation: