I got D.
There's a few ways to solve it; I prefer using tables, but there are functions on a TI-84 that'll do it for you too. The logic here is, you have a standard normal distribution which means right away, the mean is 0 and the standard deviation is 1. This means you can use a Z table that helps you calculate the area beneath a normal curve for a range of values. Here, your two Z scores are -1.21 and .84. You might notice that this table doesn't account for negative values, but the cool thing about a normal distribution is that we can assume symmetry, so you can just look for 1.21 and call it good. The actual calculation here is:
1 - Z-score of 1.21 - Z-score .84 ... use the table or calculator
1 - .1131 - .2005 = .6864
Because this table calculates areas to the RIGHT of the mean, you have to play around with it a little to get the bit in the middle that your graph asks for. You subtract from 1 to make sure you're getting the area in the middle and not the area of the tails in this problem.
I dont know if this is right but here u goo
Answer:
3 < c < 9
Step-by-step explanation:
The length of a side of a triangle cannot be negative. This eliminates the first and last options.
The addition of two sides of a triangle must be greater than the third side. In this case:
3 + 6 = 9 > c
So, the second option is correct. The third option is not correct, because, for example, c = 8 is possible
Answer:
The interval estimate is above 70%, so infer that it will be supported.
Step-by-step explanation:
The evidence that 95% confidence interval estimating the proportion of students supporting the fee increase is [0.75, 0.85] supports university officials' claim that at least 70% of the voting student population supports a fee increase.
Therefore we can infer that a fee increase will be supported.
Answer:
Simplify
![Q-[R+S]-T](https://tex.z-dn.net/?f=Q-%5BR%2BS%5D-T)
The answer is:

Step-by-step explanation:
We have the expressions:

Now, we need simplify:
![Q-[R+S]-T](https://tex.z-dn.net/?f=Q-%5BR%2BS%5D-T)
We need to replace each term by the expressions:
![7m+3n-[(11-2m)+(n+5)]-(-m-3n+8)](https://tex.z-dn.net/?f=7m%2B3n-%5B%2811-2m%29%2B%28n%2B5%29%5D-%28-m-3n%2B8%29)
We need to remember the rule of signs:



With this in mind we solve the parentheses:
![7m+3n-[(11-2m)+(n+5)]-(-m-3n+8)](https://tex.z-dn.net/?f=7m%2B3n-%5B%2811-2m%29%2B%28n%2B5%29%5D-%28-m-3n%2B8%29)
![7m+3n-[11-2m+n+5]+m+3n-8](https://tex.z-dn.net/?f=7m%2B3n-%5B11-2m%2Bn%2B5%5D%2Bm%2B3n-8)

let's group common terms

We must add and subtract common terms:

The answer is:
