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ella [17]
3 years ago
13

Find a solution to the linear equation y=-4x+36 by filling in the boxes with a valid value of x and y

Mathematics
1 answer:
lesya [120]3 years ago
8 0

Answer:

23

Step-by-step explanation

grief

tail

abridge

train

remind

habitat

gate

appointment

afford

stream

cheat

reckless

mixture

favorable

cultivate

horizon

please

garbage

show

headquarters

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Theresa has $12 in nickels and quarters. If she has the same number of each kind of coin, how many nickels and quarters does she
postnew [5]

Answer: She has 40 nickels and 40 quarters .

Step-by-step explanation:

Let be "n" the number of nickels Theresa has and "q" the number of quarters Theresa has.

You know that she has a total of $12 in nickels and quarters. In cents, this is:

\$12*100=1,200\ cents

Then, based on this you can write the following expression:

5n+25q=1,200

Since n=q, you can rewrite it as:

5n+25n=1,200

Solving for "n", you get:

30n=1,200\\\\n=\frac{1,200}{30}\\\\n=40

Therefore she has 40 nickels and 40 quarters .

7 0
3 years ago
PLEASE HELP ITS MY TRIMESTER TEST MY MOM WILL KILL ME IF I FAIL! <3 WILL MARK BRAINLIST!
Masteriza [31]

Answer:

area = area \: of \: two \: semi \: circles + area \: of \: rectangle \\  = 2( \frac{1}{2} \pi {r}^{2} ) + (l \times w) \\  = 2( \frac{1}{2}  \times 3.14 \times  { (\frac{18}{2}) }^{2} ) + (18 \times 4.5) \\  = 254.47 + 81 \\  = 335.5 \:  {ft}^{2}

3 0
3 years ago
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Write the ordered pair that describes a point 12 units down from and 7 units to the right of the origin.
emmainna [20.7K]
(-7,-12) s it both down and to the right of the origin
8 0
3 years ago
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Really need help with this pls help!!
worty [1.4K]

Let's carry this math sentence over to its natural, "shapey" element. We're going to look at each term not as an ordinary number, but as <em>the area of some shape</em>.

x² (read as "x <em>squared"</em>) can be seen as the area of a square with side lengths of x. 2x can similarly be seen as the area of a <em>rectangle </em>with a length of x and a width of 2. (Picture 1)

What's our question actually asking, though? Something about <em>perfect squares</em>. More specifically, we're looking for something to add on that'll <em>make this thing a perfect square</em>. We're trying to find a missing piece we can slot in to make a square, in other words. Problem is, our shapes don't look much like a square if we put them together right now. We need to do a little cutting and gluing first.

First, we're gonna cut the 2x rectangle lengthwise, getting two rectangles with an area of x, a length of 1, and a width of x. Next, we're going to attach them to the x² square, creating this shape that looks, strangely, like a square with a little bit missing from it (picture 2). What we're trying to do is <em>complete this square, </em>to find the area of that little missing chunk.

As it turns out, we have all the information we need for this. Notice that, using the lengths of the x rectangles, we can find that the square's dimensions are 1 x 1, which means that its area is 1 x 1  = 1.

If we tack this new area on to our original expression, we've "completed the square!" We now have a perfect square with side lengths of (x + 1) and an area of (x + 1)² (picture 3).

So, our final expression is x² + 2x + 1, and the missing constant - the area of the "missing square" we had to find to complete our larger one - is 1.

5 0
3 years ago
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The red and the blue triangles drawn on the line are similar.
zavuch27 [327]
Uh oh, this is a problem right ok whta is thus
4 0
3 years ago
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