What is the slope of the line that contains ( 5, -3) and 6, 7)? Write your answer as m=

Mathematics

1 answer:

ycow [4]2 years ago

4 0

7-(-3)=10
6-5=1
10/1
m=10
hope it helps:)

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MissSmartiez, when you're done please answer these questions.:)

BabaBlast [244]

The first one is number 2 the second one is 185.(could you also say what is in the drop down menu for the third one. The last one is Part A is 376 and part B is 1,3,4.Hoped it helped a bit :)

7 0

3 years ago

Read 2 more answers

In a group of Explore students, 38 enjoy video games, 12 enjoy going to the movies and 24 enjoy solving mathematical problems. O

Elodia [21]

Answer:

The number of students that like only two of the activities are 34

Step-by-step explanation:

Number of students that enjoy video games, A = 38

Number of students that enjoy going to the movies, B = 12

Number of students that enjoy solving mathematical problems, C = 24

A∩B∩C = 8

Here we have;

n(A∪B∪C) = n(A) + n(B) + n(C) - n(A∩B) - n(B∩C) -n(A∩C) + n(A∩B∩C)

= 38 + 12 + 24 - n(A∩B) - n(B∩C) -n(A∩C) + 8

Also the number of student that like only one activity is found from the following equation;

n(A) - n(A∩B) - n(A∩C) + n(A∩B∩C) + n(B) - n(A∩B) - n(B∩C) + n(A∩B∩C) + n(C) - n(C∩B) - n(A∩C) + n(A∩B∩C) = 30

n(A) + n(B) + n(C) - 2·n(A∩B) - 2·n(A∩C) - 2·n(B∩C) + 3·n(A∩B∩C) = 30

38 + 12 + 24 - 2·n(A∩B) - 2·n(A∩C) - 2·n(B∩C) + 24 = 30

- 2·n(A∩B) - 2·n(A∩C) - 2·n(B∩C) = -68

n(A∩B) + n(B∩C) + n(A∩C) = 34

Therefore, the number of students that like only two of the activities = 34.

8 0

3 years ago

Which number gives you an irrational product when you multiply it by 2

soldi70 [24.7K]

<h2>Explanation:</h2><h2></h2>

An irrational number is a number that can't be written as a simple fraction while a rational number is a number that can be written as the ratio of two integers, that is, as a simple fraction. So in this case we have the number 2 which is ration, and we can multiply it by an irrational number $n$ such that the product is an irrational number. So any irrational number will meet our requirement because the product of any rational number and an irrational number will lead to an irrational number. For instance:

$\bullet \ 2\sqrt{2} \\ \\ 2 \ is \ rational \\ \\ \sqrt{2} \ is \ irrational \\ \\ 2\sqrt{2} \ is \ irrational \\ \\ \\ \bullet \ 2\pi \\ \\ 2 \ is \ rational \\ \\ \pi \ is \ irrational \\ \\ 2\pi \ is \ irrational$