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sweet-ann [11.9K]
3 years ago
8

Help pls this is for my math test.

Mathematics
2 answers:
Nadusha1986 [10]3 years ago
7 0

Answer:

The answer is D. 14.

Step-by-step explanation:

When you plug in x = 14, it would work, but if you plug in any of the others, it would not.

<h2><u><em>PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>
Stells [14]3 years ago
5 0

Answer:

D is the answers for the question

Step-by-step explanation:

please mark me as brainlest

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The license plates on all karts in MarioLand contain three numbers followed by three letters. If you know that the MarioLand num
iogann1982 [59]

Answer:

It can be created 1575 license plated with at least one three-piece palindrome.

Step-by-step explanation:

If a license plates has at least one three-piece palindrome, we have the following cases:

1. The license plate just has a palindrome in the three numbers: The number license plates for this case can be calculated using the rule of multiplication as:

<u>   5              </u>*<u>      5      </u>* <u>      1       </u>* <u>        3         </u>*<u>      3       </u>*<u>      2       </u>=  450

1st Number        2nd        3rd          1st Letter       2nd           3rd

For have a palindrome in the numbers, the first and the 3rd number need to be the same. So, we have 5 digits for the first and the 2nd Number and one digit for the 3rd Number.

On the other hand, if the palindrome is just in the numbers, the 3rd letter need to be different from the 1st. So we have 3 options for the 1st and the 2nd letter and 2 options for the 3rd letter.

At the same way, we can calculated the number of license plates for the other cases:

2. The license plate just has a palindrome in the three letters:

<u>   5              </u>*<u>      5      </u>* <u>      4       </u>* <u>        3         </u>*<u>      3       </u>*<u>      1       </u>=  900

1st Number        2nd        3rd          1st Letter       2nd           3rd

3. The license plate has a palindrome in the three numbers and in the letters:

<u>   5              </u>*<u>      5      </u>* <u>      1       </u>* <u>        3         </u>*<u>      3       </u>*<u>      1       </u>=  225

1st Number        2nd        3rd          1st Letter       2nd           3rd

Then, It can be created 1575 license plates with at least one three-piece palindrome and it is calculated as:

450 + 900 + 225 = 1575

5 0
3 years ago
Simplify (12x3 - 8x2) - (3x3 + 9x2 + x - 7).
Gekata [30.6K]

Answer:

9x^3-17x^2-x+7

Step-by-step explanation:

Distribute the negative you'll get

(12x^3-8x^2)+(-3x^3-9x^2-x+7)

Combine like terms

12x^3-3x^3=9x^3 , -8x^2-9x^2=-17x^2 , -x , +7

Putting it all together:

9x^3-17x^2-x+7

3 0
3 years ago
A piece of wire of length 5050 is​ cut, and the resulting two pieces are formed to make a circle and a square. Where should the
algol [13]

Answer:

x should be cut at 2221.5 to minimize the total combined area, and at 5050 to maximize it.

Step-by-step explanation:

Let x be the length of wire that is cut to form a circle within the 5050 wire, so 5050 - x would be the length to form a square.

A circle with perimeter of x would have a radius of x/(2π), and its area would be

A_c = \pir^2 = \pi (\frac{x}{2pi})^2 = \frac{x^2}{4\pi}

A square with perimeter of 5050 - x would have side length of (5050 - x)/4, and its area would be

A_s = (\frac{5050 - x}{4})^2 = \frac{(5050 - x)^2}{16}

The total combined area of the square and circles is

\sum A = A_c + A_s = \frac{x^2}{4\pi} + \frac{(5050 - x)^2}{16}

To find the maximum and minimum of this, we just take the 1st derivative, and set it to 0

A' = \frac{2x}{4\pi} + \frac{-2(5050-x)}{16} = 0

\frac{x}{2\pi} - \frac{5050 - x}{8} = 0

Multiple both sides by 8π and we have

4x - 5050\pi + x\pi = 0

x(4 + \pi) = 5050\pi

x = \frac{5050\pi}{4 + \pi} = 2221.5

At x = 2221.5:

A = \frac{x^2}{4\pi} + \frac{(5050 - x)^2}{16} = 392720 + 500026 = 892746 [/tex]

At x = 0, A = 5050^2/16 = 1593906

At x = 5050, A = \frac{5050^2}{4\pi} = 2029424

As 892746 < 1593906 < 2029424, x should be cut at 2221.5 to minimize the total combined area, and at 5050 to maximize it.

3 0
3 years ago
How many sunsets of at least one element does a set of six elements have
Lesechka [4]

Answer:

63

Step-by-step explanation:

Given:

a set of six elements  

The solution would be like this for this specific problem:

number of subsets of n elements = 2^n

(2^6) - 1

= 64 – 1

= 63

7 0
3 years ago
Jenny's company has 15 trucks in two different sizes. There are small trucks with 6 wheels and large trucks with 12 wheels. Her
stira [4]

Answer: 8

Step-by-step explanation:

6 0
3 years ago
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