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Andre45 [30]
3 years ago
6

A student fills her burette with NaOH to the 2.5 mL mark. She titrated her sample of the NaOH until she reaches the endpoint (i.

e. all the acid has been neutralized by the NaOH). The volume marking on her burette - at the endpoint - is 52.5 mL. How many mL of NaOH did she use to reach the endpoint
Chemistry
1 answer:
VashaNatasha [74]3 years ago
8 0

Answer:

She used 50 mL of NaOH to reach the endpoint.

Explanation:

Assuming the burette is filled to the point marked 3.30 ml, You would record the initial point as 3.30 ml:

If at the end of the titration the level of the NaOH is at 20.30 mL; Subtract the initial reading from the final burette reading to get how many mL was used to reach an end point.

That is  20.3 - 3.3 = 17.00 mL

Therefore, the titration would have required 17.00 mL.

Remember that you should read the number that is at the bottom of the meniscus and at an eye level in order to avoid error.

Initial mark = 2.5 mL

Final mark = 52.5 mL.

volume used = 52.5 - 2.5

                            = 50 mL

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Answer:

The unbalanced chemical equation: H₂O₂ → H₂O + O₂.

The balanced chemical equation: H₂O₂ → H₂O + 1/2O₂.

Explanation:

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  • It is can be catalyzed by using yeast.

The unbalanced chemical equation: H₂O₂ → H₂O + O₂.

The balanced chemical equation: H₂O₂ → H₂O + 1/2O₂.

1.0 mol of H₂O₂ is decomposed to 1.0 mol of H₂O and 0.5 mol of O₂.

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6. The fusion of 4 H-1 nuclei to produce two positrons and one other nuclei.​
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Explanation:

Normally, fusion involves two heavy hydrogen nuclides but since we have 4 light hydrogen nuclides, two of which underwent positron emission, thus changing two protons into neutrons plus 2 positrons and 2 neutrinos. The resulting nucleus from this fusion reaction is an He-4 nucleus.

3 0
2 years ago
The heat of combustion of ethane is -337.0kcal at 25 degrees celsius. what is the heat of the reaction when 3g of ethane is burn
Ghella [55]

Answer:

Q = -33.6kcal .

Explanation:

Hello there!

In this case, according to the equation for the calculation of the total heat of reaction when a fixed mass of a fuel like ethane is burnt, we can write:

Q=n*\Delta _cH

Whereas n stands for the moles and the other term for the enthalpy of combustion. Thus, for the required total heat of reaction, we first compute the moles of ethane in 3 g as shown below:

n=3g*\frac{1mol}{30.08g}=0.1mol

Next, we understand that -337.0kcal is the heat released by the combustion of 1 mole of ethane, therefore, to compute Q, we proceed as follows:

Q=0.1mol*-337.0\frac{kcal}{mol}\\\\Q=-33.6kcal

Best regards!

8 0
2 years ago
The [H+] of a solution can be determined from the pH using the equation: [H+] = 10 - pH ... Where: [H+] = hydrogen ion concentra
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Answer:

pH = -log₁₀ [H⁺]

Explanation:

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As you write in the question, [H⁺] = 10^(-pH)

Using logarithm law (log (m^(p) = p log(m):

log₁₀ [H⁺] = -pH

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<h3>pH = -log₁₀ [H⁺]</h3>
8 0
3 years ago
Consider the following mechanism for the reaction between nitric oxide and ozone:
swat32

Answer:

A .  2 O₃(g) + 2 NO   ⇒  2 O₂ (g) + 2 NO₂(g)

B . Yes

C.   O and NO₃

Explanation:

A. The overall reaction is obtained by adding the individual steps in the reaction mechanism where we will get the reactants and product and the intermediates will cancel.

Thus, adding 1+ 2 +3 we get

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From this definition it follows that O(g) and NO₃ are reaction intermediates.

C. O and NO₃

6 0
3 years ago
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