Answer:
Decomposition reaction = Those reactions in which single compound decompose down to give two or more products are called decomposition reaction .
Explanation:
Those reactions in which single compound decompose down to give two or more products are called decomposition reaction .
For the Decomposition reaction to take place , <u><em>a large amount of energy ias needed</em></u>. This is because for decomposition bonds are required to breaks. Hence energy is needed to break the bonds as they have strong force of attraction.
They occur in presence of HEAT , LIGHT , ELECTRICITY.
examples of decomposition reactions are:
Here only one CaCO3 is producing two substances which are : CaO and CO2
This is also known as decompositon of Calcium carbonate and it require a lot of heat energy.
This is also a decomposition reaction , This occur in the presence of sunlight
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Answer:
C
Explanation:
if we were to followw the IUPAC
Answer:
b. 11.90 Liters
Explanation:
- The balanced equation for the mentioned reaction is:
<em>3O₂ + 4Al → 2Al₂O₃,</em>
It is clear that 3.0 moles of O₂ react with 4.0 moles of Al to produce 2.0 Al₂O₃.
- Firstly, we need to calculate the no. of moles (n) of 36.12 g of Al₂O₃:
<em>n = mass/molar mass</em> = (44.18 g)/(101.96 g/mol) = <em>0.4333 mol.</em>
<u><em>using cross multiplication:</em></u>
3.0 mol of O₂ produces → 2.0 mol of Al₂O₃.
??? mol of O₂ produces → 0.4333 mol of Al₂O₃.
<em>∴ The no. of moles of O₂ needed to produce 36.12 grams of Al₂O₃</em> = (3.0 mol)(0.4333 mol)/(2.0 mol) = <em>0.65 mol.</em>
- Now, we can find the volume of O₂ used during the experiment:
We can use the general law of ideal gas: <em>PV = nRT.</em>
where, P is the pressure of the gas in atm (P = 1.3 atm).
V is the volume of the gas in L (V = ??? L).
n is the no. of moles of the gas in mol (n = 0.65 mol).
R is the general gas constant (R = 0.0821 L.atm/mol.K),
T is the temperature of the gas in K (T = 290 K).
<em>∴ V = nRT/P </em>= (0.65 mol)(0.0821 L.atm/mol.K)(290 K)/(1.3 atm) = <em>11.9 L.</em>
<em>So, the right choice is: b. 11.90 Liters.</em>
