3x - 2y = 1
2x + 2y = 4
Add the second equation to the first
5x = 5
2x + 2y = 4
Divide the first equation by 5
x = 1
2x + 2y = 4
Subtract the first equation from the second
x = 1
x + 2y = 3
Subtract the first equation from the second again
x = 1
2y = 2
Divide the second equation by 2
x = 1
y = 1
<h3>
So, the solution is x = 1 and y = 1 {or: (1, 1)} </h3>
Answer:
6x² + 4x + 10
Step-by-step explanation:
(2x - 2)(3x + 5)
2x(3x + 5) - 2(3x + 5)
6x² + 10x - 6x + 10
6x² + 4x + 10 ans.
hope this helps you !
Answer:
Step-by-step explanation:
The graph is done using Desmos. Just by substitution x = 1 will force the graph to go to y = 0, but graphs are not always that good. This one gets 1.111
to get y = 0. I'd use 1 if you had to answer it and a computer will mark it.
Answer:
6.928 or 6.93
Step-by-step explanation:
\sqrt{8^{2}-4^{2}}
LHL in not equal to RHL , Therefore the limit does not exists , Option D is the answer.(none)
<h3>What is the limit of a function ?</h3>
The limit of a function at a certain point is the value that the function approaches as the argument of the function approaches the same point.
It is given that
lim x->2 for f(x)

f(x) = 2x+1 x ≤2
f(x)= x² , x >2
When both the function tends to 2
Left Hand Limit
f(x) = 2 *2 +1
f(x) = 5
Right Hand Limit
f(x) = x² ,
f(x) = 4
LHL in not equal to RHL , Therefore the limit does not exists.
To know more about Limit of a Function
brainly.com/question/7446469
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