-12 + 18 = 70 - 64 or(-12+18)+(6*12)-2
Vcylinder-Vsphere=water
Vcylinder=hpir^2
Vsphere=(4/3)pir^3
given
cylinderradius=30 and h=100
Vcylinder=100pi30^2=100pi900=90000pi
let's leave it in terms of pi for more exactness
sphereradius=12
Vsphere=(4/3)pi12^3=2304pi
cylinder-sphere=90000pi-2304pi=87696pi
using pi=3.14
water=275365.44 cubic cm
last option is corrrect
the awser is (-2)(8 + 6) + (-3)
Answer:
y=-1/2x-3
Step-by-step explanation:
Quadratic functions are second-order equations of the form y=ax^2+bx+c. Their graphs form parabolas. The defining characteristic of a quadratic is that the acceleration of the outputs is a constant.
