If you notice, the positive fraction, is the one with the "x" variable in it, that simply means, the hyperbola is opening over the x-axis, so is a horizontal one, therefore
A square picture frame measures 36 inches on each side. The actual wood trim is 2 inches wide. The photograph in the frame is su
rrounded by a bronze mat that measures 5 inches. What is the maximum area of the photograph
2 answers:
We need to figure out how much of the total area of the picture frame is usable. To do this, we need to figure out what is taken up by the frame and the mat.
The frame is 36 inches on a side.
We know the frame is 2 inches. We know that the the mat is 5 inches.
This means that on each 36 inch side, 4 inches are taken up by the frame (2 each side) and 10 inches by the mat (again, 5 each side). So the total length left is
36 - 4 - 10 = 32 - 10 = 22.
The maximum area of the photograph is therefore 22 x 22 = 484 square inches.
The frame is 36 inches on a side.
We know the frame is 2 inches. We know that the the mat is 5 inches.
This means that on each 36 inch side, 4 inches are taken up by the frame (2 each side) and 10 inches by the mat (again, 5 each side). So the total length left is
36 - 4 - 10 = 32 - 10 = 22.
The maximum area of the photograph is therefore 22 x 22 = 484 square inches.
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