Answer:
the gravitational force JWST will feel from the Sun is 37.785 Newton { leftward }
Explanation:
Given that;
distance of earth from the telescope r1 = 1.494 × 10⁹ m
and the Sun will be 1.49598 × 10¹¹ m further away
so r2 = r1 + 1.49598 × 10¹¹
r2 = 1.494 × 10⁹ m + 1.49598 × 10¹¹ m = 1.51092 × 10¹¹ m
mass of sun Ms = 1.9884 × 10³⁰ kg
mass of earth Me = 5.945× 10²⁴ kg
mass of JWST Mj = 6500 kg
What is the gravitational force JWST will feel from the Sun (strength and direction)?
the gravitational force of the sun will be attractive based on Newton law of gravitational force; so
Fjs = GMjMs / r2²
constant G = 6.674 × 10⁻¹¹ Nm²/kg²
Force on the JWST by the sun will be;
Fjs = GMjMs / r2² { leftward}
we substitute
Fjs = [(6.674 × 10⁻¹¹ Nm²/kg²)(6500 kg )(1.9884 × 10³⁰ kg)] / (1.51092 × 10¹¹ m)²
= (8.62587804 × 10²³) / ( 2.28287925 × 10²² )
= 37.785 Newton { leftward }
Therefore, the gravitational force JWST will feel from the Sun is 37.785 Newton { leftward }
