Answer:
The appropriate response will be "Length must be increased by 0.012%".
Explanation:
The given values is:
ΔT = 5 s/day
Now,
⇒ ![\frac{\Delta T}{T} =\frac{5}{24\times 60\times 60}](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20T%7D%7BT%7D%20%3D%5Cfrac%7B5%7D%7B24%5Ctimes%2060%5Ctimes%2060%7D)
On multiplying both sides by "100", we get
⇒ ![\frac{\Delta T}{T}\times 100 =\frac{500}{24\times 60\times 60}](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20T%7D%7BT%7D%5Ctimes%20100%20%3D%5Cfrac%7B500%7D%7B24%5Ctimes%2060%5Ctimes%2060%7D)
⇒
(%)
∵ ![T=2\pi\sqrt{\frac{l}{g} }](https://tex.z-dn.net/?f=T%3D2%5Cpi%5Csqrt%7B%5Cfrac%7Bl%7D%7Bg%7D%20%7D)
On substituting the values, we get
⇒
% =
%
On applying cross multiplication, we get
⇒
% =
%
⇒ = ![2\times 0.05787](https://tex.z-dn.net/?f=2%5Ctimes%200.05787)
⇒ = ![0.011574](https://tex.z-dn.net/?f=0.011574)
⇒ =
%
The period will be the same if the amplitude of the motion is increased to 2a
What is an Amplitude?
Amplitude refers to the maximum extent of a vibration or oscillation, measured from the position of equilibrium.
Here,
mass m is attached to the spring.
mass attached = m
time period = t
We know that,
The time period for the spring is calculated with the equation:
![T = 2\pi \sqrt{\frac{m}{k} }](https://tex.z-dn.net/?f=T%20%3D%202%5Cpi%20%5Csqrt%7B%5Cfrac%7Bm%7D%7Bk%7D%20%7D)
Where k is the spring constant
Now if the amplitude is doubled, it means that the distance from the equilibrium position to the displacement is doubled.
From the equation, we can say,
Time period of the spring is independent of the amplitude.
Hence,
Increasing the amplitude does not affect the period of the mass and spring system.
Learn more about time period here:
<u>brainly.com/question/13834772</u>
#SPJ4
P=W/t
P=Power
W=Work
t=Time
Convert 16 minutes in seconds:
16 mins = 960 secs
P=6720/960=7.23 W [Watt]
Answer:
law of conservation of energy is that a perpetual motion machine of the first kind cannot exist, that is to say, no system without an external energy supply can deliver an unlimited amount of energy to its surroundings
Explanation:
Hope it helps.
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Answer:
(a) 3.24 w (b) 44.44 ohm
Explanation:
It is given that car draws 0.27 A current so current I = 0.27 A
The system has a voltage of 12 V
(a) Electrical power = voltage ×current ![=12\times 0.27=3.24W](https://tex.z-dn.net/?f=%3D12%5Ctimes%200.27%3D3.24W)
(b) The resistance is defined as the ratio of voltage and current
So resistance ![R=\frac{V}{I}=\frac{12}{0.27}=44.44 ohm](https://tex.z-dn.net/?f=R%3D%5Cfrac%7BV%7D%7BI%7D%3D%5Cfrac%7B12%7D%7B0.27%7D%3D44.44%20ohm)