If the frequency is much higher the capacitor will not get fully charged before the wave fall to zero states .here the time period is very low so the graph or output will look like this
If the frequency is much low => the time period is very high=>
After the first capacitor is fully charged, it stays in the same state (up to V). When the voltage reaches zero, the discharge begins. After being fully discharged, it stays in the same state until it reaches the next state because it has a very long time span.
Note that for all practical purposes the decay curve of the RC discharge circuit is exponential and the voltage across the capacitor plates is much less than 1% of the initial starting value after 5-time constants. please. Discharged.
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Answer:
<em><u>make something go down under the surface of liquid or a soft substance</u></em>
Explanation:
hope this helps you!!
Answer:
Relation between initial speed of bullet and height h is given as
Explanation:
As we know that system of block and bullet swings up to height h after collision
So we have
so we have
so speed of the block + bullet just after the impact is given by above equation
Now we also know that there is no force on the system of bullet + block in the direction of motion
So we can use momentum conservation
now we have
Answer:
B = E/c = 14.04T₁ = 11 pT
Explanation:
We know c = E/B where E = maximum electric field = 3.30 × 10⁻³ V/m, B = maximum magnetic field and c = speed of light
B = E/c also c = fλ = λ/T where λ = wavelength = 235 μm = 235 × 10⁻⁶ m and T = period
c = λ₁/T₁ = λ₂/T₂ T₂ = 2.8T₁ where λ₁,λ₂ are the initial and final wavelengths and T₁,T₂ are the initial and final periods.
T₁ = λ₁/c = 235 × 10⁻⁶ m/3 × 10⁸ m/s = 7.833 × 10⁻¹³ s = 0.7833 ps
T₂ = 2.8T₁ = 2.8 × 7.833 × 10⁻¹³ s = 21.93 × 10⁻¹³ s = 2.193 ps
λ₁/T₁ = λ₂/2.8T₁
λ₂ = 2.8λ₁ = 2.8 × 235 μm = 658 μm
c = λ₂/T₂ = 2.8λ₁/2.8T₁ = λ₁/T₁ , since the speed of light c is constant.
B = E/c = E/λ₁/T₁ = ET₁/λ₁
B = ET₁/λ₁ = 3.30 × 10⁻³ V/m × T₁/235 × 10⁻⁶ m = 14.04T₁ Tesla
B = 14.04 × 7.833 × 10⁻¹³ s = 10.99 × 10⁻¹² T ≅ 11 pT
The calculated mutual inductance is 8.544 x 10⁻⁵ H.
Two coils have a mutual inductance of 1 henry when emf of 1 volt is induced in coil 1 and when the current flowing through coil 2 is changing at the rate of one ampere per second.
Length of the solenoid= 5.0 cm
Area of cross-section=1.0 cm²
no of spaced turns=300 turns
turns of insulated wire=180 turns
Mutual inductance (M) = μ₀μr N1N2 A/ L
=(4xπx 10⁻⁷) x (6.3 x 10⁻³) x 300 x 180 x 1/ 5
=79.12 x 10⁻¹⁰ x 54000 / 5
=8.544 x 10⁻⁵ H
hence, the mutual inductance is 8.544 x 10⁻⁵ H.
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