Answer:
Work done = 35467.278 J
Explanation:
Given:
Height of the cone = 4m
radius (r) of the cone = 1.2m
Density of the cone = 600kg/m³
Acceleration due to gravity, g = 9.8 m/s²
Now,
The total mass of the cone (m) = Density of the cone × volume of the cone
Volume of the cone = 
thus,
volume of the cone = 
= 6.03 m³
therefore, the mass of the cone = 600 Kg/m³ × 6.03 m³ = 3619.11 kg
The center of mass for the cone lies at the 
times the total height
thus,
center of mass lies at, h' = 
Now, the work gone (W) against gravity is given as:
W = mgh'
W = 3619.11kg × 9.8 m/s² × 1 = 35467.278 J
Answer:
95.51 N
Explanation:
First, find the mass in kg:
Fg = 585 N
Fg = m*g
585 N = m*9.8 m/s^2
<u>m = 59.69 kg</u>
Then, to find your weight (Fg) on the moon, you use the same equation of
Fg(moon) = m*g, except this time g = 1.60 m/s^2
Fg(moon) = 59.69 kg * 1.60 m/s^2
Fg(moon) = 95.51 N
Hope this helps!! :)
I believe it would be 3 amps.
Answer: In young's double slit experiment that uses monochromatic light the interference pattern formed has Central bright band with alternate dark and bright band That is option B.
Explanation: In this young experiment two small slits Namely a and b are formed on the screen and a monochromatic light is focused on them. Wavelets come out of of this lets scintillating and overlapping each other. This we get from huyginns principal, thus forming alternate dark and bright bands with bright band at center and all bands are about one meter apart.
