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KonstantinChe [14]
3 years ago
6

Identify the percent of change as an increase or a decrease. 1/4 to 1/2 Find the percent of change. Round to the nearest tenth o

f a percent if necessary.
Mathematics
1 answer:
galben [10]3 years ago
5 0

Answer:

Increase by 100%

Step-by-step explanation:

To find the percent increase/decrease:

  1. Subtract the original value from the new value.
  2. Divide by the original value.
  3. Multiply the decimal by 100 to convert to a percent.

Follow these steps below. Notice the fractions 1/2 and 1/4 have been converted to decimals to more easily work with them. Remember 1/2 = 0.5 and 1/4 = 0.25.

1/2 - 1/4 = 0.5 - 0.25 = 0.25

0.25/0.25 = 1

1*100 = 100%

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Answer:

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Someone came into a store and stole 100 dollars from the register. The person returned 5 minutes later and purchased 70 dollars
Nataliya [291]
Think of it this way. Ignore for now that $100 was stolen.

The purchase of the $70 item for $100 cash with $30 change is a perfectly fair purchase. The store received $100 cash, and the store gave $70 worth of merchandise plus $30 cash.There was no loss to the store there.

The fact that $100 in cash was stolen earlier from cash register means the loss is $100. The legitimate transaction does not affect the loss.

If you have a hard time understanding the loss is $100, then think of it this way.
Reverse the order of the two happenings.

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That customer later came back to the store and stole $100 from the cash register.

Here we see clearly that the loss is exactly $100. It is simply the $100 stolen from the cash register.
5 0
3 years ago
Pls help me with one and two pls
jeyben [28]

Answer:

3ac-a+2b

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Step-by-step explanation:

3*2*4-2+2*1

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3 years ago
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Read 2 more answers
Suppose a and b are the solutions to the quadratic equation 2x^2-3x-6=0. Find the value of (a+2)(b+2).
KonstantinChe [14]

Answer:

(a+2)(b+2) = 4

Step-by-step explanation:

We are given the following quadratic equation:

2x^2-3x-6=0

Let a a and b be the solution of the given quadratic equation.

Solving the equation:

2x^2-3x-6=0\\\text{Using the quadratic formula}\\\\x = \dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\\\\\text{Comparing the equation to }ax^2 + bx + c = 0\\\text{We have}\\a = 2\\b = -3\\c = -6\\x = \dfrac{3\pm \sqrt{9-4(2)(-6)}}{4} = \dfrac{3\pm \sqrt{57}}{4}\\\\a = \dfrac{3+\sqrt{57}}{4}, b = \dfrac{3-\sqrt{57}}{4}

We have to find the value of (a+2)(b+2).

Putting the values:

(a+2)(b+2)\\\\=\bigg(\dfrac{3+\sqrt{57}}{4}+2\bigg)\bigg(\dfrac{3-\sqrt{57}}{4}+2\bigg)\\\\=\bigg(\dfrac{11+\sqrt{57}}{4}\bigg)\bigg(\dfrac{11-\sqrt{57}}{4}\bigg)\\\\=\dfrac{121-57}{156} = \dfrac{64}{16} = 4

3 0
3 years ago
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