Answer:
The play will be more appealing to a younger audience.
Explanation:
A younger audience will more likely appreciate current pop hits rather than classical score.
Answer:
Convection, and boundaries
Explanation:
In this lab, you modeled how plates move. The plates that make up Earth’s lithosphere move because of convection . You also saw how plates interact with each other. The interactions between plates form plate boundaries of which there are three main types.
1. The molar mass of the unknown gas obtained is 0.096 g/mol
2. The pressure of the oxygen gas in the tank is 1.524 atm
<h3>Graham's law of diffusion </h3>
This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e
R ∝ 1/ √M
R₁/R₂ = √(M₂/M₁)
<h3>1. How to determine the molar mass of the gas </h3>
- Rate of unknown gas (R₁) = 11.1 mins
- Rate of H₂ (R₂) = 2.42 mins
- Molar mass of H₂ (M₂) = 2.02 g/mol
- Molar mass of unknown gas (M₁) =?
R₁/R₂ = √(M₂/M₁)
11.1 / 2.42 = √(2.02 / M₁)
Square both side
(11.1 / 2.42)² = 2.02 / M₁
Cross multiply
(11.1 / 2.42)² × M₁ = 2.02
Divide both side by (11.1 / 2.42)²
M₁ = 2.02 / (11.1 / 2.42)²
M₁ = 0.096 g/mol
<h3>2. How to determine the pressure of O₂</h3>
From the question given above, the following data were obtained:
- Volume (V) = 438 L
- Mass of O₂ = 0.885 kg = 885 g
- Molar mass of O₂ = 32 g/mol
- Mole of of O₂ (n) = 885 / 32 = 27.65625 moles
- Temperature (T) = 21 °C = 21 + 273 = 294 K
- Gas constant (R) = 0.0821 atm.L/Kmol
The pressure of the gas can be obtained by using the ideal gas equation as illustrated below:
PV = nRT
Divide both side by V
P = nRT / V
P = (27.65625 × 0.0821 × 294) / 438
P = 1.524 atm
Learn more about Graham's law of diffusion:
brainly.com/question/14004529
Learn more about ideal gas equation:
brainly.com/question/4147359
Answer:
See explanation
Explanation:
On the pH scale acidity ranges from pH values of 0-6.9. Natural rain water is slightly acidic due to the presence of carbon dioxide in the atmosphere which is an anhydride of carbonic acid.
CO2(g) + H2O(l) -------> H2CO3(aq)
B. The equations that turn sulfur to sulfuric acid are;
S(l) + O2(g) -----> SO2(g)
2SO2(l) + O2(g) -----> 2SO3(g)
SO3(g) + H2SO4(l) -----> H2S2O7(l)
H2S2O7(l) + H2O(l) ----> 2H2SO4(l)
-
At pH 6, H^+ concentration = 1 * 10^-6 M
At pH 2, H^+ concentration = 1 * 10^-2 M
Hence;
1 * 10^-2/1 * 10^-6
= 10^4 times more acidic
