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3 years ago

Convert 2.54 moles of CaCl, to liters.

Chemistry

1 answer:

Agata [3.3K]3 years ago

3 0

2.54 moles of CaCl occupies 56.89 liters volume

Explanation:

Each mole of any gas occupies 22.4 liters volume at STP.
STP is defined as the standard temperature and pressure and those standard values are zero degree and one atmospherics pressure
22.4 liters is a constant number as Avogadro's number which is nothing but 6.022* $10^{23}$ .
Hence, to convert 2.54 moles just multiply it with 22.4 L
That is, 22.4*2.54= 56.89 L
So, 2.54 moles of CaCl occupies 56.89 L volume space

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Answer:

Elemental gold to have a Face-centered cubic structure.

Explanation:

From the information given:

Radius of gold = 144 pm

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Assuming the structure is a face-centered cubic structure, we can determine the density of the crystal by using the following:

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density d = 19.41 g/cm³

Similarly; For a body-centered cubic structure

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where;

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$144 = \dfrac{\sqrt{3}}{4}a$

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In a unit cell, Volume V = a³

V = (332.56 pm)³

V = 3.68 × 10⁷ pm³

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$density = \dfrac{mass}{volume}$

$density = \dfrac{ 2 \ atm ( 196.97 \ g/mol) (\dfrac{1 \ mol }{6.022 \times 10^{23} \ atoms})}{3.68 \times 10^{-23} \ cm^3}$

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Consider the following reaction: A(g)⇌2B(g). Find the equilibrium partial pressures of A and B for each of the following differe

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Answer:

a. Kp=1.4

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$P_{B}=0.556 atm$

b.Kp=2.0 * 10^-4

$P_{A}=0.495atm$

$P_{B}=0.00995 atm$

c.Kp=2.0 * 10^5

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Explanation:

For the reaction

A(g)⇌2B(g)

Kp is defined as:

$Kp=\frac{(P_{B})^{2}}{P_{A}}$

The conditions in the system are:

A B

initial 0 1 atm

equilibrium x 1atm-2x

At the beginning, we don’t have any A in the system, so B starts to react to produce A until the system reaches the equilibrium producing x amount of A. From the stoichiometric relationship in the reaction we get that to produce x amount of A we need to 2x amount of B so in the equilibrium we will have 1 atm – 2x of B, as it is showed in the table.

Replacing these values in the expression for Kp we get:

$Kp=\frac{(1-2x)^{2}}{x}$