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Monica [59]
3 years ago
13

Convert 2.54 moles of CaCl, to liters.

Chemistry
1 answer:
Agata [3.3K]3 years ago
3 0

2.54 moles of CaCl occupies 56.89 liters volume

Explanation:

  • Each mole of any gas occupies 22.4 liters volume at STP.
  • STP is defined as the standard temperature and pressure and those standard values are zero degree and one atmospherics pressure
  • 22.4 liters is a constant number as Avogadro's number which is nothing but 6.022* 10^{23} .
  • Hence, to convert 2.54 moles just multiply it with 22.4 L
  • That is, 22.4*2.54= 56.89 L
  • So, 2.54 moles of CaCl occupies 56.89 L volume space
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In the equilibrium constant expression for the reaction below what is the correct exponent for N2O4?
irga5000 [103]
As we have the balanced reaction equation is:

N2O4 (g) ↔ 2NO2(g)

from this balanced equation, we can get the equilibrium constant expression

KC = [NO2]^2[N2O4]^1

from this expression, we can see that [NO2 ] is with 2 exponent of  the stoichiometric and we can see that from the balanced equation as NO2
is 2NO2 in the balanced equation.

and [N2O4] is with 1 exponent of the stoichiometric and we can see that from the balanced equation as N2O4 is 1 N2O4 in the balanced equation. 

∴ the correct exponent for N2O4 in the equilibrium constant expression is 1 
7 0
3 years ago
The molar mass of glucose is 180.2 g/mol. How many grams of glucose will be produced when 132.0 g of CO2 reacts with an excess o
andriy [413]

Answer:

The mass in grams of glucose produced when 132.0 g of CO2 reacts with an excess of water is 90.1 grams

Explanation:

The chemical equation for the reaction is

6H₂O + 6CO₂  → C₆H₁₂O₆ + 6O₂

From the reaction, it is seen that 6 moles of H₂O reacts ith 6 moles of CO₂ to produce 1 mole of glucose  C₆H₁₂O₆ and 6 moles oxygen gas

The molar mass of CO₂ = 44.01 g/mol

There fpre 132.0 g contains 132.0/44.01 moles or ≅ 3 moles

However since 6 moles of CO₂ produces 1 mole of O₂, then 3 moles of CO₂ will prduce 1/6×3 or 0.5 moles of C₆H₁₂O₆

and since the molar mass (or the mass of one mole) of C₆H₁₂O₆ is 180.2 grams/mole then 0.5 mole of C₆H₁₂O₆ will have a mass of

mass of 1 mole C₆H₁₂O₆ = 180.2 g

mass of 0.5 mole C₆H₁₂O₆ = 180.2 g × 0.5 = 90.1 grams

Mass of glucose produced = 90.1 grams

7 0
3 years ago
When was the first published textbook containing a table identifying the first 33 elements
olya-2409 [2.1K]

1789 -- raité élémentaire de chimie is a textbook written by Antoine Lavoisier published in 1789 and translated into English by Robert Kerr in 1790 under the title Elements of Chemistry

5 0
3 years ago
A solution of acetic acid, CH3CO₂H(aq), is at equilibrium. How would the
s344n2d4d5 [400]

If more acetic acid were added to a solution at equilibrium, [H⁺] and [CH₃CO₂⁻] would increase to counteract the perturbation. (Option C)

<h3>How do systems at equilibrium respond to perturbation?</h3>

When a system at equilibrium suffers a perturbation, it shifts its equilibrium position to counteract such perturbation.

Let's consider a solution of acetic acid at equilibrium.

CH₃CO₂H(aq) = CH₃CO₂⁻(aq) + H⁺(aq)

If more acetic acid were added to the solution, the system will shift toward the products to counteract such an increase.

How would the system change if more acetic acid were added to the solution?

A. [H⁺] would decrease and [CH₃CO₂⁻] would increase. NO.

B. [H⁺] and [CH₃CO₂⁻] would decrease. NO.

C. [H⁺] and [CH₃CO₂⁻] would increase. YES. Both products would increase.

D. [H⁺] would increase and [CH₃CO₂⁻] would decrease. NO.

If more acetic acid were added to a solution at equilibrium, [H⁺] and [CH₃CO₂⁻] would increase to counteract the perturbation.

Learn more about equilibrium here: brainly.com/question/2943338

#SPJ1

3 0
2 years ago
As the deapth of the ocean increases the population of ocean creatures..
Trava [24]

Answer:

( A ) Increases

Explanation:

More room, basically means more creatures. Like in a bedroom, you can only fit amount of people if its small the ocean is like that with depth.

Hopefully this makes sense???

3 0
3 years ago
Read 2 more answers
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