Atom , classify ithelppoppppoeowiie
1 answer:
You might be interested in
Answer : The fuel value and the fuel density of pentane is, 49.09 kJ/g and respectively.
Explanation :
Fuel value : It is defined as the amount of energy released from the combustion of hydrocarbon fuels. The fuel value always in positive and in kilojoule per gram (kJ/g).
As we are given that:
Fuel value =
Molar mass of pentane = 72 g/mol
Fuel value =
Fuel value = 49.09 kJ/g
Now we have to calculate the fuel density of pentane.
Fuel density = Fuel value × Density
Fuel density = (49.09 kJ/g) × (0.626g/mL)
Fuel density = 30.73 kJ/mL =
Thus, the fuel density of pentane is
Answer:
2.24 L of hydrogen gas, measured at STP, are produced.
Explanation:
Given, Moles of magnesium metal, = 0.100 mol
Moles of hydrochloric acid, = 0.500 mol
According to the reaction shown below:-
1 mole of Mg reacts with 2 moles of
0.100 mol of Mg reacts with 2*0.100 mol of
Moles of must react = 0.200 mol
Available moles of = 0.500 moles
Limiting reagent is the one which is present in small amount. Thus, is limiting reagent.
The formation of the product is governed by the limiting reagent. So,
1 mole of on reaction forms 1 mole of
0.100 mole of on reaction forms 0.100 mole of
Mole of = 0.100 mol
At STP,
Pressure = 1 atm
Temperature = 273.15 K
Volume = ?
Using ideal gas equation as:
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L.atm/K.mol
Applying the equation as:
1 atm × V L = 0.100 × 0.0821 L.atm/K.mol × 273.15 K
<u>⇒V = 2.24 L</u>
2.24 L of hydrogen gas, measured at STP, are produced.