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3 years ago

How many moles of chloride ions are there in 2 moles of calcium chloride?

Chemistry

1 answer:

Oksana_A [137]3 years ago

6 0

Answer:

There are 4 moles of chloride ions in 2 moles of calcium chloride.

Explanation:

Start by writing the chemical formula of calcium chloride.

The suffix -ide in chloride means that chlorine is working as the ion Cl⁻, this is with oxidation state -1.

Calcium, being an alkaline earth metal, uses oxidation state +2, Ca²⁺

Then, two atoms of Cl are combined with one atom of calcium, because in this way each Cl atom will accept one electron from a Ca atom, which will donate its two valence electrons.

That is indicated in the chemical formula with subscripts: CaCl₂, meaning that each formula-unit of calcium chloride has 2 ions of chlorine and 1 ions of calcium, or twice the number of moles of chloride ion.

1 mol CaCl₂ : 1 mol Ca⁺ : 2 mol Cl⁻

⇒ 2 mol CaCl₂ : 2 mol Ca⁺ : 4 mol Cl⁻

Hence, there are 4 moles of chloride ions in 2 moles of calcium chloride.

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For the reaction where Δn=−1Δn=−1 , what happens after in increase in volume? ????KQ>K so the reaction shifts toward reactant

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Answer:

Explanation:

In general, an increase in pressure (decrease in volume) favors the net reaction that decreases the total number of moles of gases, and a decrease in pressure (increase in volume) favors the net reaction that increases the total number of moles of gases.

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Δn= moles of gaseous products - moles of gaseous reactants

Therefore, after the increase in volume:

If Δn= −1 ⇒ there are more moles of gaseous reactants than gaseous products. The equilibrium will be shifted towards the products, that is, from left to right, and K>Q.
If Δn= 0 ⇒ there is the same amount of gaseous moles, both in products and reactants. The system is at equilibrium and K=Q.
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3 years ago

What mass of sulfur has to burn to produce 4.5L SO2 at 300°C and 101 kPa in the following reaction?s(s)+O2(g) SO,(g)

Alex_Xolod [135]

Answer: option B. 3.07 g

Explanation:

1) given reaction:

S(s) + O₂ (g) → SO(g)

2) Balanced chemical equation:

2S(s) + O₂ (g) → 2SO(g)

3) Theoretical mole ratios:

2 mol S : 1 mol O₂ : 2 mol SO

3) number of moles of 4.5 liter SO₂ at 300°C and 101 kPa

use the ideal gas equation:

pV = nRT

with V = 4.5 liter
p = 101 kPa
T = 300 + 273.15 K = 573.15 K
R = 8.314 liter×kPa / (mol×K)

=> n = pV / (RT) =

n = [101 kPa × 4.5 liter] / [8.314 (liter×kPa) / (mol×K) × 573.15 K ]

n = 0.0954 mol SO

4) proportion with the theoretical ratio S / SO

2 mol S x
-------------- = ----------------------
2 mol SO 0.0954 mol SO

=> x = 0.0954 mol S.

5) Convert mol of S to grams by using atomic mass of S = 32.065 g/mol

mass = number of moles × atomic mass

mass = 0.0954 mol × 32.065 g/mol = 3.059 g of S

6) Therefore the answer is the option B. 3.07 g

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3 years ago