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masha68 [24]
3 years ago
14

A buffer solution is 0.310 M in H2SO3 and 0.304 M in NaHSO3. If Ka1 forH2SO4 is 1.7e-2 , what is the pH of this buffer solution

Chemistry
1 answer:
natka813 [3]3 years ago
4 0

Answer:

pH of the buffer solution is 1.76

Explanation:

To find the pH of a buffer we can use Henderson-Hasselbalch equation:

pH = pKa + log [A⁻] / [HA]

<em>Where pKa is -log Ka= 1.77 And [A⁻] is molar concentration of conjugate base, NaHSO₃ and [HA] molar concentration of weak acid, H₂SO₃</em>

<em />

Replacing values of the problem:

pH = 1.77 + log [0.304M] / [0.310M]

pH = 1.76

<h3>pH of the buffer solution is 1.76</h3>
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Answer:

<h3>The answer is 20 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

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mass = 16,000 g

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We have

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We have the final answer as

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2.2×10^8

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Overall ionic reaction:

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Equilibrium constant for the reaction: Ksp×Kw= 2.2 x 10 ^-20 × (1/(1×10^-14))^2

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2 years ago
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Answer:

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