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Kryger [21]
2 years ago
5

The normal boiling point of fingernail polish remover is 56℃. what is the vapor pressure of fingernail polish remover at the sal

on, which is kept at a temperature of 22℃ for the comfort of customers?
Chemistry
1 answer:
Elenna [48]2 years ago
7 0

The normal boiling point of fingernail polish remover is 56℃  the vapor pressure of fingernail polish remover at the salon 0.027 atmospheric pressure

<h3>What is atmospheric pressure?</h3>

The pressure exerted by the vapors due to the atmosphere as it is surrounded by it only is known as vapor pressure and its unit is atm.

As air have small molecules which forms multiple layers and create pressure.

vapor pressure = {1/T1 - 1/T2}

T1 = 56 c

T2 = 22 c

substituting the values,

vapor pressure = [ 1/ 56 - 1 / 22 ]

                         = 0.027 atm.

Therefore, the vapor pressure of nail paint remover is 0.027 atm

Learn more about vapor pressure , here:

brainly.com/question/8696772

#SPJ4

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they are the same element because they have the same number of protons and electrons,but a different number of neutrons

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Explain why the atomic number is called the fingerprint of element
Dovator [93]

Answer:

No element shares the same atomic number. The atomic number of every element is unique to itself, just like a fingerprint is unique to a human. The atomic number of element allows us to identify it, like how we can identify a person from their fingerprint.

Explanation:

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2 years ago
An unknown noble gas has a density of 5.84 g dm-3 at STP. Calculate its molar mass, and so identify the gas.
bagirrra123 [75]

The noble gas is Xenon and its molar mass is 131 g/mol.

<h3>What is the molar mass of the noble gas?</h3>

The molar mass of the noble gas is determined as follows;

Let molar mass of unknown gas be M, and mass of gas be m

Density of the noble gas, ρ = 5.8 g/dm³

density = m/V

At STP;

  • temperature, T = 273.15 K
  • pressure, P = 1 atm
  • molar gas constant, R = 0.0821 L.atmK⁻¹mol⁻¹

From ideal gas equation:

PV = nRT

where n = m/M

PV = mRT/M

M = mRT/PV

M =  0.0821 * 273.15 * 5.84/1

Molar mass of the noble gas = 131 g/mol

The noble gas is Xenon which has molar mass approximately equal to 131 g/mol.

Learn more about molar mass at: brainly.com/question/837939

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6 0
1 year ago
6. The given mass of helium occupies
marin [14]

Answer:

V2 = 35.967cm^3

Explanation:

Given data:

P1 = 0.2atm

P2 = 1.4atm

V1 = 250cm^3

V2 = ?

T1 = 10°C + 273 = 283K

T2 = 12°C + 273 = 285K

Apply combined law:

P1xV1/T1 = P2xV2/T2 ...eq1

Substituting values:

0.2 x 250/283 = 1.4 x V2/285

Solve for V2:

V2 = 14250/396.2

V2 = 35.967cm^3

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2 years ago
Nvm i got it lol how do i delete
Lady_Fox [76]

Answer:

delete what?

Explanation:

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3 years ago
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