Answer:
N2 + H2 ----------》NH3
On balancing it
N2. + 3.H2------->2.NH3
( 1 mol) (3 mol) (2 mol)
1 mol of nitrogen reacts with 3 mol of hydrogen to give 2 mol of ammonia.
Likewise,
20 litres of nitrogen reacts with 60 litres of hydrogen to give 40 litres of Ammonia.
Hence, the answer is 40 Litres.
Answer:
2.04 mol
Explanation:
At STP, 1 mole = 22.4 L
45.6 L of H2 * (1 mole of H2 / 22.4 L ) = 2.04 mol
Answer:
2
Explanation:
Tried out 1, but couldn't get whole numbers on the right side then, so went up to 2, worked
all four numbrrs: 2, 7, 4, 6
The 7 for oxygen got adjusted in the last step of the thinking, because it's the simplest to adjust.
since there are different prime numbers (or rather numbers that don't share prime factors) in the set, the numbers can't be revived by the same number and still give whole numbers as results (they can't be smaller)
Answer:
Explanation:
Hello,
In this case, since in a dilution process the moles of the solute must remain unchanged, we use the volumes and molarities as shown below:
Clearly, the concentrated solution is 12M and the diluted solution is 0.5 M, thus, the volume of the concentrated solution we should take is:
Best regards.
